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8th class > Cubes and Cube Roots > Cubes

Cubes

You know that the word ‘cube’ is used in geometry. A cube is a solid figure which has all its sides .

How many cubes of side 1 cm will make a cube of side 2 cm?

How many cubes of side 1 cm will make a cube of side 3 cm ?

Consider the numbers 1, 8, 27, ... These are called perfect cubes or cube numbers.

Can you say why they are named so? Each of them is obtained when a number is multiplied by taking it times.

We note that:

1 = 1 × 1 × 1 =

8 = 2 × 2 × 2 =

27 = 3 × 3 × 3 =

We get: 53 = 5 × 5 × 5 =

Therefore, 125 is a number.

Is 9 a cube number?

As 9 = × and there is no natural number which multiplied by taking three times gives 9.

We can see also that 2 × 2 × 2 = and 3 × 3 × 3 = .

This shows that 9 is not a perfect cube.

The following are the cubes of numbers from 1 to 10:

NumberCube
113 = 1
223 = 8
333 = 27
443 = 64
553 =
NumberCube
663 =
773 =
883 =
993 =
10103 =

There are only ten perfect cubes from 1 to 1000. How many perfect cubes are there from 1 to 100? Observe the cubes of even numbers. Are they all even? What can you say about the cubes of odd numbers?

Fill the given below table to know the cubes of the numbers from 11 to 20.

NumberCube
11113 = 1331
12123 = 1728
13133 = 2197
14143 = 2744
15153 =
NumberCube
16163 =
17173 =
18183 =
19193 =
20203 =

Consider a few numbers having 1 as the one’s digit (or unit’s). Find the cube of each of them. What can you say about the one’s digit of the cube of a number having 1 as the one’s digit?

Similarly, explore the one’s digit of cubes of numbers ending in 2, 3, 4, ... , etc. Based on your observations, drop the given below numbers in the correct category:

Find the one’s digit of the cube of each of the following numbers

Instructions

3331
8888
149
276
1005
1024
77
4564
5022
53
1
2
3
4
5
6
7
8
9

Some interesting patterns

  1. Adding consecutive odd numbers

Observe the following pattern of sums of odd numbers.

1 =1 =
3 + 5 =8 =
7 + 9 + 11 =27 =
13 + 15 + 17 + 19 =64 =
21 + 23 + 25 + 27 + 29 =125 =

Is it not interesting? How many consecutive odd numbers will be needed to obtain the sum as 103?

Express the following numbers as the sum of odd numbers using the above pattern?

Instructions

63 = = 31 + + + + +
Starting from = 53, we take the sum of the next six odd natural numbers i.e. 31,33,35,37,39 and 41.

Instructions

73= = 43 + + + + + +
Starting from = 63, we take the sum of the next seven odd natural numbers i.e. 43,45, 47, 49, 51, 53 and 55.

Instructions

83 = = 57 + + + + + + +
Starting from = 73, we take the sum of the next eight odd natural numbers i.e. 57,59, 61, 63, 65, 67, 69 and 71.

Consider the following pattern:

2313 = 1 + 2 × 1 × 3

3323 = 1 + 3 × 2 × 3

4333 = 1 + 4 × 3 × 3

Using the above pattern, find the value of the following:

Instructions

7363 = 1 + × × 3
We find the product of the two bases (i.e. 7 and 6) and further multiply the product with 3 and add 1 to it.

Instructions

123113 = 1 + × × 3
We find the product of the two bases (i.e. 12 and 11) and further multiply the product with 3 and add 1 to it.

Instructions

203193 = 1 + × × 3
We find the product of the two bases (i.e. 20 and 19) and further multiply the product with 3 and add 1 to it.

Instructions

513503 = 1 + × × 3
We find the product of the two bases (i.e. 51 and 50) and further multiply the product with 3 and add 1 to it.

Cubes and their prime factors

Consider the following prime factorisation of the numbers and their cubes.

Prime factorisation of a numberPrime factorisation of its cube
4 = 2 × 243 = 64 = 2 × 2 × 2 × 2 × 2 × 2= 3 × 3
6 = 2 × 363 = 216 = 2 × 2 × 2 × 3 × 3 × 3= 3 × 3
15 = 3 × 5153 = 3375 = 3 × 3 × 3 × 5 × 5 × 5= 3 × 3
12 = 2 × 2 × 3123 = 1728 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3= 3 × 3 × 3

Observe that each prime factor of a number appears times in the prime factorisation of its cube.

In the prime factorisation of any number, if each factor appears three times then, is the number a perfect cube?

Think about it. Is 216 a perfect cube?

By prime factorisation, 216 = 2 × 2 × 2 × 3 × 3 × 3

Each factor appears times.

216 = 23×33=2×33

= 63 which is a perfect cube!

Is 729 a perfect cube? 729 = × × × × ×

, 729 a perfect cube.

Now let us check for 500?

Prime factorisation of 500 is 2 × 2 × 5 × 5 × 5 (There are three 5’s in the product but only two 2’s.)

So, 500 a perfect cube.

Example 1: Is 243 a perfect cube ?

243 = × × × ×

In the above factorisation 3 × 3 remains after grouping the 3’s in triplets.

Therefore, 243 a perfect cube.

Which of the following are perfect cubes?

Instructions

400
3375
8000
15625
9000
6859
2025
10648
Perfect Cube
Not Perfect Cube

Smallest multiple that is a perfect cube

Raj made a cuboid of plasticine. Length, breadth and height of the cuboid are 15 cm, 30 cm, 15 cm respectively.

Anu asks how many such cuboids will she need to make a perfect cube? Can you tell?

Raj said, Volume of cuboid is

15 × 30 × 15 = 3 × 5 × 2 × 3 × 5 × 3 × 5

= 2 × 3 × 3 × 3 × 5 × 5 × 5

Since there is only one 2 in the prime factorisation. So we need 2 × 2, i.e., to make it a perfect cube.

Therefore, we need such cuboids to make a cube.

Example 2: Now, is 392 a perfect cube? If not, find the smallest natural number by which 392 must be multiplied so that the product is a perfect cube

392 = × × × × (Enter the factors is ascending order)

Since, the prime factor 7 does not appear in a group of three, 392 a perfect cube.

To make it a cube, we need one more .

So, it becomes: 392 × 7 = 2 × 2 × 2 × 7 × 7 × 7 = which is a perfect cube.

Hence, the smallest natural number by which 392 should be multiplied to make a perfect cube is .

Example 3: Is 53240 a perfect cube? If not, then by which smallest natural number should 53240 be divided so that the quotient is a perfect cube?

53240 = × × × × × × (Enter factors in increasing order)

The prime factor 5 does not appear in a group of three. So, 53240 a perfect cube.

In the factorisation 5 appears only time. If we divide the number by 5, then the prime factorisation of the quotient will not contain 5. So,

53240 ÷ 5 = 2 × 2 × 2 × 11 × 11 × 11

Hence, the smallest number by which 53240 should be divided to make it a perfect cube is .

The perfect cube in that case is i.e. 532405

Example 4: Is 1188 a perfect cube? If not, by which smallest natural number should 1188 be divided so that the quotient is a perfect cube?

1188 = × × × × ×

The primes and do not appear in groups of three. So, 1188 a perfect cube.

In the factorisation of 1188, the prime 2 appears only times and the prime 11 appears .

So, if we divide 1188 by 2 × 2 × 11 = , then the prime factorisation of the quotient will not contain 2 and 11. Hence, the smallest natural number by which 1188 should be divided to make it a perfect cube is .

And the resulting perfect cube is 1188 ÷ 44 = = 33

Example 5: Is 68600 a perfect cube? If not, find the smallest number by which 68600 must be multiplied to get a perfect cube.

68600 = × × × × × × × (Enter factors in increasing order)

So, 68600 a perfect cube. To make it a perfect cube we multiply it by .

68600 × 5 = 2 × 2 × 2 × 5 × 5 × 5 × 7 × 7 × 7 =

Think, Discuss and Write

Check which of the following are perfect cubes.

Instructions

2700
16000
64000
900
125000
36000
21600
10000
27000000
1000
Perfect Cube
Not Perfect Cube

What pattern do you observe in these perfect cubes ?

This pattern shows that perfect cubes often have cube roots that are whole numbers, and in cases where the number is a multiple of 10, its cube root also tends to be a neat multiple of 10.

The number of zeros in the perfect cubes is a multiple of .