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7th class > Integers > Exercise 1.1

Exercise 1.1

1.Write down a pair of integers whose:

(a) sum is –7 :

  1. -3 + = −7

2. 5 + ()= −7

(b) difference is –10 :

1. 3 − = −10

2. -5 − = −10

(c) sum is 0:

1. 6 + ()= 0

2. -8 + = 0

2.

(a) Write a pair of negative integers whose difference gives 8 :

  1. -2 −() = 8

(b) Write a negative integer and a positive integer whose sum is –5 .

1) + 2 = −5

(c) Write a negative integer and a positive integer whose difference is –3.

1) -1 − = −3

3. In a quiz, team A scored – 40, 10, 0 and team B scored 10, 0, – 40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?

Instruction

Calculate the Total Scores
Team A Scores : −40,10,0.
Sum the scores : ++ = .
Team B Scores : 10,0,-40.
Sum the scores: ++=.
The calculation confirms that both teams are equal in their scores and reinforces that the order of adding integers does not affect the final sum.
Thus, we can say that integers can be added in any order, and the sum will be the same.

4. Fill in the blanks to make the following statements true:

(i) (–5) + (– 8) = (– 8) + ().

(ii) –53 + = –53

(iii) 17 + () = 0

(iv) [13 + (– 12)] + () = 13 + [(–12) + (–7)].

(v) (– 4) + [15 + (–3)] = [– 4 + 15] + ().