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9th class > Linear Equations in Two Variables > Exercise 4.1

Exercise 4.1

Q1

  1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. (Take the cost of a notebook to be Rs. x and that of a pen to be Rs. y).

Sol

Solution:

Let the cost of a notebook be = ₹ x

Let the cost of a pen be = ₹ y

Given: The cost of a notebook is twice the cost of a pen i.e Cost of a notebook = 2 × cost of a pen

= ×

x = 2y ⇒ x - 2y = 0

Thus, x2y=0 is the linear equation in two variables to represent the statement, ‘The cost of a notebook is twice the cost of a pen.

Q2

  1. Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:

(i) 2x + 3y = 9.3\overline{5}

(ii) x – y5 – 10 = 0

(iii) –2x + 3y = 6

(iv) x = 3y

(v) 2x = –5y

(vi) 3x + 2 = 0

(vii) y – 2 = 0

(viii) 5 = 2x

Sol

(i) 2x + 3y = 9.3\overline{5}

The equation 2x + 3y = 9.3\overline{5} can be written as:

2x + 3y - 9.3\overline{5} = 0

Comparing we get: a = , b = and c =

(ii) x – y5 – 10 = 0

The equation xy510 = 0 can be written as:

x+15y+10=0

Comparing we get: a = , b = c =

(iii) –2x + 3y = 6

Re-arranging the equation, we get: 2x+3y6=0

Now, comparing we get: a = , b = and c =

(iv) x = 3y

Re-arranging the equation, we get: x3y=0

Now comparing we get: a = , b = , c =

(v) 2x = –5y

Re-arranging the equation, we get: 2x+5y=0

Now, comparing we get: a = , b = and c =

(vi) 3x + 2 = 0

Now comparing we get: a = , b = , c =

(vii) y – 2 = 0

Now comparing we get: a = , b = and c =

(viii) 5 = 2x

Re-arranging the equation, we get: 2x5 = 0

Now comparing we get: a = , b = and c =