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9th class > Number Systems > Operations on Real Numbers

Operations on Real Numbers

You have learnt, in earlier classes, that rational numbers satisfy the commutative, associative and distributive laws for addition and multiplication.

Moreover, if we add, subtract, multiply or divide (except by zero) two rational numbers, we still get a rational number.

In other words, rational numbers are ‘closed’ with respect to addition, subtraction,multiplication and division.

It turns out that irrational numbers also satisfy the commutative, associative and distributive laws for addition and multiplication.

However, the sum, difference, quotients and products of irrational numbers are not always irrational.

For example: ( 6+6,22),3·3 and 1717 are rationals.

Let us look at what happens when we add and multiply a rational number with an irrational number.

For example: 3 is irrational.

What about 2 + 3 and 23? Since 3 has a and decimal expansion, the same is true for 2 + 3 and 23 .

Therefore, both 3 and 23 are also irrational numbers.

Examples 11: Check whether 75,75, 2 + 21, π − 2, are irrational numbers or not.

Instruction

5 = ... , 2 = ..., π = ...
Then 75= ...,75 = 7555=755 = ...
2 + 21 = ..., π – 2 = ...
All these are non-recurring decimals. So, all these are numbers.

Now, let us see what generally happens if we add, subtract, multiply, divide, take square roots and even nth roots of these irrational numbers, where n is any natural number. Let us look at some examples.

Examples 12: Add 22+53 and 233.

Instruction

22+53 + 233
= 22+2+5333
= 2+12+533 = 2 + 3
Thus, we have found the answer.

Examples 13: Multiply 65by25

Instruction

65×25 = 6 × × 5 × 5 = × =
We have found the answer.

Examples 14: Divide 815 by 23.

Instruction

815÷23 = 83×523
=
We have found the answer.

These examples may lead you to expect the following facts, which are true:

(i) The sum or difference of a rational number and an irrational number is .

(ii) The product or quotient of a non-zero rational number with an irrational number is .

(iii) If we add, subtract, multiply or divide two irrationals, the result may be or irrational.

We now turn our attention to the operation of taking square roots of real numbers.

Recall that, if a is a natural number, then a = b means b2 = a and b > 0. The same definition can be extended for real numbers.

Let a > 0 be a number. Then a = b means b2 = a and b > 0.

We saw how to represent n for any positive integer n on the number line. We now show how to find x for any given positive real number x geometrically.

Let x be a positive rational number. Let AB be of a length 'x' units on the numberline.

Now, extend AB upto a point C on the numberline such that BC is 1 unit.

Taking AC of length , find the mid point D. Thus, AD = CD = .

Using D as the center, draw a semi-circle/ circle and also extend AC further, to see where this circle intersects the numberline.

From point B, draw a perpendicular intersecting the circle. Join BE.

The length of the segment BE is equal to x. Now using the mouse, drop the point E on the numberline.

But how do we get that? Let's find out!

We can see that DE = x+12

From the figure, we can see: DB = DC - BC = x+12 - 1 =

Looking at triangle DEB, using pythagoras theorem, we get:

DE2 = DB2 + BE2

x+122 = x122 + BE2

BE2 = x+122 - x122

= x2+2x+1x2+2x14

=

Thus, BE = x.

We would like to now extend the idea of square roots to cube roots, fourth roots and in general nth roots, where n is a positive integer.

Recall your understanding of square roots and cube roots from earlier classes.

What is 38?

Well, we know it has to be some positive number whose cube is 8, and you must have guessed 38 = .

Let us try \sqrt[5]{243}. Do you know some number b such that b5=243?

The answer is . Therefore, \sqrt[5]{243} = .

From these examples, can you define \sqrt[a]{n} for a real number a > 0 and a positive integer n?

Let a > 0 be a real number and n be a integer. Then \sqrt[a]{n} = b, if bn = a and b > 0.

Note that the symbol ‘· ’ used in 2,38,\sqrt[a]{n}, etc. is called the radical sign.

We now list some identities relating to square roots, which are useful in various ways. You are already familiar with some of these from your earlier classes. The remaining ones follow from the distributive law of multiplication over addition of real numbers, and from the identity x+yxy=x2y2, for any real numbers x and y.

Let a and b be positive real numbers.

Then

(i) ab=ab

(ii) ab=ab

(iii) a+b=ab = a-b

(iv) a+bab=a2b

(v) a+bc+d = ac+ad+bc+bd

(vi) a+b2=a+2ab+b

Let us look at some particular cases of these identities.

Example 15: Simplify the following expressions:

Instruction

(i) 5+72+5 = + 55 + 27 + 35
(ii) 5+555= 52 - 52 = - =
(iii)3+72 = 32 + 23 7 + 72 = + 221 + = + 221
(iv) 11711+7 = 112 - 72 = - =

Remark : Note that ‘simplify’ in the example above has been used to mean that the expression should be written as the sum of a rational and an irrational number.

We end this section by considering the following problem. Look at 12

Example 16: Rationalise the denominator of 12

Solution : We want to write 12 as an equivalent expression in which the denominator is a rational number. We know that 2 .

2 is rational. We also know that multiplying 12 by 22 will give us an equivalent expression, since 22 = .

Using this, we get:

12 = 12 × 22 = .

Example 17: Rationalise the denominator of 12+3.

Solution : We use the Identity (iv) given earlier.

Multiply and divide 12+3 by rationalise. We get: 12+3×2343 = -3.

Thus, the answer is 2 -3

Example 18: Rationalise the denominator of 535

Solution : Here we use the Identity (iii) given earlier. So,

535=535×3+53+5=53+535 which give us:

= 3+5.

Example 19: Rationalise the denominator of 17+32

Solution :

17+32=17+32×732732=7324918

= .

So, when the denominator of an expression contains a term with a square root (or a number under a radical sign), the process of converting it to an equivalent expression whose denominator is a rational number is called rationalising the denominator.