Exercise 12.1
1. Find the common factors of the given terms.
2. Factorise the following expressions.
(i) 7x – 42
7x – 42 = 7×x -
(ii) 6p – 12q
6p – 12q =
= 2×3(p - 3q) =
(iii) 7 a 2 + 14 a
(iv)
- Take out the common factor(s) product :
- Thus, factorised form =
- Taking out the common factor out of the bracket
- Which gives us the above answer
(v)
- Take out the common factor(s) product :
- Thus, factorised form =
- Taking out the common factor out of the bracket
- Which gives us the above answer
(vi) 5 x 2 y − 15 xy 2
= 5×x(x×y - 3×y×y) =
(vii) 10 a 2 − 15 b 2 + 20 c 2
(viii)
- Take out the common factor(s) product :
- Thus, factorised form =
- Taking out the common factor out of the bracket
- Which gives us the above answer
(ix)
- Take out the common factor(s) product :
- Thus, factorised form =
- Taking out the common factor out of the bracket
- Which gives us the above answer
(x)
- Take out the common factor(s) product :
- Thus, factorised form =
- Taking out the common factor out of the bracket
- Which gives us the above answer
3. Factorise:
(i) x 2 + xy + 8 x + 8 y
(ii) 15xy – 6x + 5y – 2
- We can see that the factorization needs re-grouping.
- Regrouping the expression
- Take out the common factors from the corresponding terms
- Thus, factorised form =
- Which gives us the above factorised answer
(iii) ax + bx – ay – by
- The factorization doesn't need re-grouping.
- Take out the common factors from the corresponding terms
- Thus, factorised form =
- Which gives us the above factorised answer
(iv) 15pq + 15 + 9q + 25p
- We can see that the factorization needs re-grouping.
- Regrouping the expression
- Take out the common factors from the corresponding terms
- Thus, factorised form =
- Which gives us the above factorised answer
(v) z – 7 + 7xy – xyz
- We can see that the factorization needs re-grouping.
- Regrouping the expression
- Take out the common factors from the corresponding terms
- Thus, factorised form =
- Which gives us the above factorised answer