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Chapter 10: The Other Side Of Zero > The Token Model

The Token Model

Using tokens for addition

In Bela's Building of Fun, the lift attendant is bored. To entertain himself, he keeps a box containing lots of positive (red) and negative (green) tokens. Each time he presses the '+' button, he takes a positive token from the box and puts it in his pocket. Similarly, each time he presses the '–' button, he takes a negative token and puts it in his pocket.

He starts on the floor (Floor 0) with an empty pocket. After one hour, he checks his pocket and finds 5 positive and 3 negative tokens. On which floor is he now?

He must have pressed '+' five times and '–' 3 times and +5+3= .

So, he is at Floor +2 now.

Here is another way to do the calculation.

Lets remove 3 blue-dots from them. Remove blue-dots by clicking and adding negative-dots.

As you see, when you remove three from 5 you are left with 2.

This is represented in math as 5-3=2

A positive token and a negative token cancel each other, because the value of this pair of tokens together is . These two tokens in his pocket meant that he pressed '+' once and '–' once, respectively, and these cancel each other. We say that a positive and a negative token make a 'zero pair'. When you remove all the zero pairs, you are left with two positive tokens,

so +5+3=+2.

We can perform any such addition using tokens!

Example: Add + 5 and – 8.

Lets remove 8 blue-dots from them. Remove blue-dots by clicking and adding negative-dots.

As you see, when you remove eight from 5 you are left with .

From the picture, we see that we can remove five zero pairs, and we are then left with –3. Therefore +5+8=.

1. Complete the additions using tokens.

a. +6++4 =

b. 3+2 =

c. +5+7 =

d. 2++6 =

2. Cancel the zero pairs in the following two sets of tokens. On what floor is the lift attendant in each case? What is the corresponding addition statement in each case?

a. 3 positive tokens, 5 negative tokens → Floor ,

Statement: +3+5=

b. 6 positive tokens, 3 negative tokens → Floor ,

Statement: +6+3=

Using tokens for subtraction

We have seen how to perform addition of integers with positive tokens and negative tokens. We can also perform subtraction using tokens!

Example: Let us subtract: (+5) – (+4).

This is easy to do. From 5 positives take away 4 positives to see the result.

+5+4=

Example: Let us subtract: (–7) – (–5).

Is 75 the same as 7++5?

75=

Example: Let us subtract: (+5)–(+6).

Put down 5 positives.

But there are not enough tokens to take out 6 positives!

To get around this issue, we can put out an extra zero pair (a positive and a negative), knowing that this does not change the value of the set of tokens.

Now, we can take out 6 positives!

See what is left:

We conclude that +5+6=.

Figure it Out

1. Evaluate the following differences using tokens. Check that you get the same result as with other methods you now know:

a. +10+7 =

b. 84 =

c. 94 =

d. +9+12 =

e. 57 =

f. 26 =

2. Complete the subtractions:

a. 57 =

b. +10+13 =

c. 79 =

d. +3+8 =

e. 27 =

f. +3+15 =

Example: + 4 – (–6).

Start with 4 positives.

We have to take out 6 negatives from these. But there are not enough negatives.

This is not a problem. We add some zero pairs as this does not change the value of the set of tokens.

But how many zero pairs? We have to take away 6 negatives so we put down zero pairs:

Now we can take away 6 negatives:

Therefore,

+4 (–6) = .

Figure it Out

1. Try to subtract: –3– (+5).

How many zero pairs will you have to put in?

What is the result?

2. Evaluate the following using tokens.

a. 3+10 =

b. +87 =

c. 5+9 =

d. 9+10 =

e. +64 =

f. 2+7 =