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6th class > Ratio and Proportion > Unitary Method

Unitary Method

Consider the following situations:

Example 1

Two friends Reshma and Seema went to market to purchase notebooks. Reshma purchased 2 notebooks for 24 rupees . What is the price of one notebook?

Solution :

Cost of 2 notebooks is rupees.

Therefore, cost of 1 notebook = 24÷2 = Rs. .

Now, if you were asked to find cost of 5 such notebooks. It would be = Rs. 12 × = Rs.

Example 2

A scooter requires 2 litres of petrol to cover 80 km. How many litres of petrol is required to cover 1 km? These are examples of the kind of situations that we face in our daily life. How would you solve these?

Solution :

Reconsider the second example: We want to know how many litres are needed to travel 1 km.

For 80 km, petrol needed = litres.

Therefore to travel 1 km, petrol needed = 280 = litres

Now, if you are asked to find how many litres of petrol are required to cover 120 km?

Then petrol needed =140 × 120 litres = litres.

The method in which first we find the value of one unit and then the value of required number of units is known as Unitary Method.

Let's try out a few more problems.

Try these

TimeDistance travelled by KaranDistance travelled by Kriti
2 hours8 km6km
1 hour4km km
4 hours km km

We see that,

Distance travelled by Karan in 2 hours = 8 km

Distance travelled by Karan in 1 hour = 82 km = km

Therefore, distance travelled by Karan in 4 hours = 4 × 4 = km

Similarly, to find the distance travelled by Kriti in 4 hours, first find the distance travelled by her in 1 hour.

If the cost of 6 cans of juice is ₹ 210 , then what will be the cost of 4 cans of juice?

Solution :

Cost of 6 cans of juice = ₹ 210

Therefore, cost of one can of juice = 2106 = ₹

Therefore, cost of 4 cans of juice = 35 × 4 = ₹ .

Thus, cost of 4 cans of juice is ₹ 140.

A motorbike travels 220 km in 5 litres of petrol. How much distance will it cover in 1.5 litres of petrol?

Solution :

In 5 litres of petrol, motorbike can travel 220 km

Therefore in 1 litre of petrol, motor bike travels = / km

Therefore in 1.5 litres, motorbike travels = 2205 x 1.5 km =2205 x 1510 km = km

Thus, the motorbike can travel 66 km in 1.5 litres of petrol.

If the cost of a dozen soaps is Rs. 153.60, what will be the cost of 15 such soaps?

Solution :

We know that 1 dozen =

Thus, cost of 12 soaps = Rs.153.60

Therefore, cost of 1 soap = / = Rs.

Total cost of 15 soaps = Rs. 12.80 × 15 = Rs.

Thus, cost of 15 soaps is Rs. 192.

Cost of 105 envelopes is Rs 350. How many envelopes can be purchased for Rs 100?

Solution :

In Rs. 350, the number of envelopes that can be purchased =

Therefore in Rs. 1, number of envelopes that can be purchased = /

In Rs. 100, the number of envelopes that can be purchased = 105350 × =

Thus, 30 envelopes can be purchased for Rs. 100.

A car travels 90 km in 212 hours. How much time is required to cover 30 km with the same speed? Also find the distance covered in 2 hours with the same speed.

Solution :

212 hours = hours (fraction form) = × minutes = minutes.

Thus, 90 km is covered in 150 minutes.

Therefore, 1 km can be covered in 15090 minutes.

Therefore, 30 km can be covered = 15090 × minutes = minutes

Thus, 30 km can be covered in 50 minutes.