Exercise 10.1
(1) An algebraic expression is a single term or a combination of terms connected by the symbols '+' (plus) or '–' (minus).
(2) If every term of an expression is a constant term, then the expression is called a
(3) An algebraic expression containing
(4) The
(5) The degree of any constant term is
(6) The
(7) If no two terms of an expression are alike then the expression is said to be in its
(8) In an expression, if the terms are arranged in a manner such that the degrees of the terms are in descending order then the expression is said to be in
(9) The sum of two or more like terms is a like term with a numerical coefficient equal to the
(10) The difference between two like terms is a like term with a numerical coefficient equal to the
1. Find the rule which gives the number of matchsticks required to make the following patterns-
(i) A pattern of letter 'H'
Answer:
Here we have to find rule for pattern of letter 'H'
Let, the number of matchsticks =
We required
Rule for pattern of letter 'H' = 3
(ii) A pattern of letter 'V'
Answer:
Here we have to find rule for pattern of letter 'V'
Let, the number of matchsticks = m
We required
Rule for pattern of letter 'V' = 2
2. Given below is a pattern made from coloured tiles and white tiles.
(i) Draw the next two figures in the pattern above.
Answer:
Figure 4: The cross shape extends, each arm has 4 tiles (including the center), so the cross is larger.
Figure 5: The cross shape extends further, each arm has 5 tiles (including the center).
(Drawings to be done by student in notebook or on paper.)
(ii) Fill the table given below and express the pattern in the form of an algebraic expression.
| Figure Number | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Number of coloured tiles | 4 |
Answer:
Here we have to express the pattern in the form of an algebraic expression.
For Figure 1, the number of coloured tiles =
Let the figure number be n.
Rule for number of coloured tiles =
The pattern in the form of an algebraic expression:
Now, let's fill the table:
When n = 1: 4n = 4 × 1 =
When n = 2: 4n = 4 × 2 =
When n = 3: 4n = 4 × 3 =
When n = 4: 4n = 4 × 4 =
When n = 5: 4n = 4 × 5 =
| Figure Number | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| No. of coloured tiles | 4 | 8 | 12 | 16 | 20 |
(iii) Fill the table given below and express the pattern in the form of an algebraic expression.
| Figure Number | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| No. of total tiles | 5 |
Answer:
Here we have to express the pattern in the form of an algebraic expression.
For Figure 1, the number of total tiles =
Let the figure number be n.
Rule for number of total tiles =
The pattern in the form of an algebraic expression:
Now, let's fill the table:
When n = 1: 4n + 1 = 4 × 1 + 1 =
When n = 2: 4n + 1 = 4 × 2 + 1 =
When n = 3: 4n + 1 = 4 × 3 + 1 =
When n = 4: 4n + 1 = 4 × 4 + 1 =
When n = 5: 4n + 1 = 4 × 5 + 1 =
| Figure Number | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| No. of total tiles | 5 | 9 | 13 | 17 | 21 |
3. Write the following statements using variables, constants and arithmetic operations.
(i)
6 more than p
Answer:
6 more than p =
(ii)
‘x' is reduced by 4
Answer:
‘x' is reduced by 4 =
(iii)
8 subtracted from y
Answer:
8 subtracted from y =
(iv)
q multiplied by ‘-5'
Answer: {.reveal(when="blank-2")}q multiplied by ‘-5' =
(v)
y divided by 4
Answer: {.reveal(when="blank-3")}y divided by 4 =
(vi)
One-fourth of the product of 'p' and 'q'
Answer: {.reveal(when="blank-4")}One-fourth of the product of 'p' and 'q' =
(vii)
5 added to the three times of 'z'
Answer: {.reveal(when="blank-5")}5 added to the three times of 'z' =
(viii)
x multiplied by 5 and added to '10'
Answer: {.reveal(when="blank-6")}x multiplied by 5 and added to 10 =
(ix)
5 subtracted from two times of 'y'
Answer: {.reveal(when="blank-7")}5 subtracted from two times of 'y' =
(x)
y multiplied by 10 and added to 13
Answer: {.reveal(when="blank-8")}y multiplied by 10 and added to 13 =
4. Write the following expressions in statements.
(i)
x + 3
Answer: {.reveal(when="blank-0")}x + 3 =
(ii)
y - 7
Answer: {.reveal(when="blank-1")}y - 7 =
(iii)
10l
Answer: {.reveal(when="blank-2")}10l =
(iv)
x/5
Answer: {.reveal(when="blank-3")}x/5 =
(v)
3m + 11
Answer: {.reveal(when="blank-4")}3m + 11 =
(vi)
2y - 5
Answer: {.reveal(when="blank-5")}2y - 5 =
5. Some situations are given below. State the number in situations is a variable or constant?
Example: Our age – its value keeps on changing so it is an example of a variable quantity.
(i)
The number of days in the month of January
Answer: {.reveal(when="blank-0")}The number in this situation is
(ii)
The temperature of a day
Answer: {.reveal(when="blank-1")}The number in this situation is
(iii)
Length of your classroom
Answer: {.reveal(when="blank-2")}The number in this situation is
(iv)
Height of the growing plant
Answer: {.reveal(when="blank-3")}The number in this situation is