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Congruency of Triangles > Exercise 8.3

Exercise 8.3

1. In following pairs of triangles, find the pairs which are congruent? Also, write the criterion of congruence.

(i)

Solution:

Let's analyze ΔABC and ΔRPQ:

AB = = 6.5 cm

∠B = ∠ = 70°

∠C = ∠ = 60°

Therefore, ΔABC and ΔRPQ are congruent by rule

(ii)

Solution:

Let's analyze ΔABD and ΔCDB:

BD = (common side)

∠ABD = ∠ = 20°

∠DBC = ∠ = 30°

Therefore, ΔABD and ΔCDB are congruent by rule

(iii)

Solution:

Let's analyze ΔABQ and ΔCDQ:

AB = = 5.5 cm

∠BAQ = ∠ = 60°

AQ = (common point Q)

Therefore, ΔABQ ≅ ΔCDQ by criterion

(iv)

Solution:

Let's analyze ΔABC and ΔDEF:

∠A = °

∠B = °

∠C = ° (180° - 70° - 50°)

Similarly in ΔDEF:

∠D = °

∠E = °

∠F = ° (180° - 70° - 50°)

Although all angles are equal: {.reveal(when="blank-5")}• ∠A = ∠D = 70° {.reveal(when="blank-5")}• ∠B = ∠E = 50° {.reveal(when="blank-5")}• ∠C = ∠F = 60°

Therefore, the triangles are as AAA only proves similarity

2. In the adjacent figure: (i) Are ΔABC and ΔDCB congruent? (ii) Are ΔAOB congruent to ΔDOC? Also identify the relation between corresponding elements and give reason for your answer.

(i)

Solution:

Let's analyze both pairs of triangles:

In ΔABC and ΔDCB: ∠BAC = ∠ = 30°

∠ACB = ∠ = 50°

AC = (given)

Therefore, ΔABC and ΔDCB are congruent by rule

(ii)

In ΔAOB and ΔDOC:

AO = (given)

BO = (given)

∠AOB = (vertically opposite angles)

Therefore, ΔAOB ≅ ΔDOC by criterion

The corresponding elements are:

• AO =

• BO =

• ∠AOB =

• ∠OAB =

• ∠OBA =

This congruence proves that O is equidistant from points A, B, C, and D