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Powers and Exponents > Exercise 11.2

Exercise 11.2

1. Simplify the following using laws of exponents.

Answer

(i)

(i) 210×24

Answer:

Let's use the law of exponents for multiplication:210×24 = (10+4)

210+4= 2

(ii)

(ii) 32×324

Answer:

First, let's simplify 324:324=3(×)

32×4=3

Now, multiply by 32:32×38= 3(+)

32+8=3

(iii)

(iii) 5752

Answer:

Let's use the law of exponents for division:5752=5-

57−2=5

(iv)

(iv) 92×918×910

Answer:

Let's use the law of exponents for multiplication: 92×918×910 = 9(++)

92+18+10=9

(v)

(v) 354×353×358

Answer:

Let's use the law of exponents for multiplication: 354×353×358 = (3/5)(++)

354+3+8= (3/5)

(vi)

(vi) −33×−310×−37

Answer:

Let's use the law of exponents for multiplication: −33×−310×−37= (-3)(++)

−33+10+7= (−3)

(vii)

(vii) 322

Answer:

Let's use the law of exponents for powers: 322= 3(×)

32×2= 3

(viii)

(viii) 24×34

Answer:

Let's use the law of exponents for same exponents: 24×34=2×34

2×34= 6

(ix)

(ix) 24a×25a

Answer:

Let's use the law of exponents for multiplication: 24a×25a= 2(+)

24a+5a= 2

(x)

(x) 1023

Answer:

Let's use the law of exponents for powers: 1023 = 10(×)

102×3= 10

(xi)

(xi) −5625

Answer:

Let's use the law of exponents for powers: −5625= (-5/6)(×)

−562×5= (−5/6)

(xii)

(xii) 23a+7×27a+3

Answer:

Let's use the law of exponents for multiplication: 23a+7×27a+3= 2(a++a+)

23a+7+7a+3= 2a +

(xiii)

(xiii) 235

Answer:

Let's write the numerator and denominator with exponents: 235 = 2 / 3

25= and 35=

235=32243

(xiv)

(xiv) −33×−53

Answer:

Let's use the law of exponents for multiplication: −33×−53= [(-3) × (-5)]

−3×−5=

153 =

(xv)

(xv) −46−43

Answer:

Let's use the law of exponents for division: −46−43 = (-4)(-)

−46−3 = (-4) =

(xvi)

(xvi) 97915

Answer:

Let's use the law of exponents for division: 97915= 9( - )

97−15 = 9

(xvii)

(xvii) −65−69

Answer:

Let's use the law of exponents for division: −65−69= (-6)( - )

−65−9 = (-6)

(xviii)

(xviii) −77×−78

Answer:

Let's use the law of exponents for multiplication: −77×−78 = (-7)( + )

−77+8 = (-7)

(xix)

(xix) −644

Answer:

Let's use the law of exponents for powers: −644= (-6)(×)

`(-6)^(4×4) = (-6)

(xx)

(xx) ax×ay×az

Answer:

Let's use the law of exponents for multiplication: ax×ay×az= a( + + )

ax+y+z

2. By what number should 3−4 be multiplied so that the product is 729?

Answer:

Let the required number be .

Then, 3−4 × x =

We know that 729 = 3

Solving for x:

x = 36 ÷ 3

x = 36-(-4)

x = 3 +

x = 3

Therefore, 3−4 should be multiplied by 310 to get 729.

If 56 × 52x = 510, then find x.

Answer:

Given: 56 × 52x = 510

Using the law of exponents for multiplication (add the exponents): 5 + x = 510

Since the bases are equal, their exponents must be equal: 6 + 2x =

Solving for x:

2x = -

2x =

x = 4 ÷ 2 =

Therefore, x = 2

Evaluate 20 + 30

Answer:

We know that any number raised to the power of 0 is equal to

Therefore:

20 =

30 =

Now, adding these values:

20 + 30 = 1 + 1 =

Therefore, 20 + 30 = 2

5. Simplify xaxba×xbxaa×xaxab

Answer:

First, use the law xmxn=xm−n:

Step 1: Simplify the first term

xaxba=xa−ba=xaa−b = x(-)

Step 2: Simplify the second term

xbxaa=xb−aa=xab−a = x(-a)

Step 3: Simplify the third term

xaxab=xa−ab=x0×b = x =

Step 4: Multiply all terms together

xa2−ab×xab−a2×1=xa2−ab+ab−a2 = x =

Therefore, the answer is .

6. State true or false and justify your answer.

Answer

(i)

(i) 100×1011=1013

100×1011 = 102×1011 = 102+11 = 10

Therefore, the statement is

(ii)

(ii) 32×43=125

Left side: 32×43 = 9×64 =

Right side: 125 =

Since 576 ≠ 248832, the statement is

(iii)

(iii) 50=1000000

Any non-zero number raised to power 0 equals

50 =

1000000 =

Therefore, the statement is

(iv)

(iv) 43=82

43 =

82 =

Therefore, the statement is

(v)

(v) 23>32

23 =

32 =

Since 8 < 9, the statement is

(vi)

(vi) −24>−34

−24 =

−34 =

Since 16 < 81, the statement is

(vii)

(vii) −25>−35

−25 =

−35 =

Since -32 > -243, the statement is