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Chapter 5: Comparing Quantities using Proportion > Exercise 5.1

Exercise 5.1

1. Find the ratio of the following

i. Smita works in office for 6 hours and Kajal works for 8 hours in her office. Find the ratio of their working hours.

Solution:

Ratio of Smita's working hours to Kajal's working hours = 6 hours : 8 hours

We can simplify this ratio by divding both sides by their greatest common divisor, which is .

6 : 8 = () : () = :

Therefore, the ratio of their working hours is .

ii. One pot contains 8 litres of milk while the other contains 750 millilitres.

Solution:

First, we need to convert the quantities to the same unit. Let's convert litres to millilitres. We know that 1 litre = millilitres.

So, 8 litres = 8 × 1000 millilitres = millilitres.

Now we can find the ratio:

Ratio of milk in the first pot to the second pot = ml : ml

We can simplify this ratio by dividing both sides by their greatest common divisor, which is :

8000 : 750 = () : () = :

Therefore, the ratio of the quantities of milk is .

iii. Speed of a cycle is 15 km/h and the speed of a scooter is 30 km/h.

Solution:

Ratio of speed of cycle to speed of scooter = 15 km/h : 30 km/h

We can simplify this ratio by dividing both sides by their greatest common divisor, which is .

15 : 30 = () : () = :

Therefore, the ratio of their speeds is .

2. If the compound ratio of 5:8 and 3:7 is 45:x. Find the value of x.

Solution:

The compound ratio of two ratios a:b and c:d is given by .

In this case, the compound ratio of 5:8 and 3:7 is (5 × 3) : (8 × 7) = : .

We are given that this compound ratio is equal to : .

Therefore: 15 : 56 = 45 : x

We can set up a proportion:

= 45/x

Cross-multiply:

= 45 × 56

15x =

x = 252015

x =

Therefore, the value of x is 168.

3. If the compound ratio of 7:5 and 8:x is 84:60. Find x.

Solution:

The compound ratio of 7:5 and 8:x is (7×8):(5×x) = : .

We are given that this compound ratio is 84 : 60. So:

56 : 5x = 84 : 60

We can set up a proportion:

565x = /

Cross-multiply:

56 × = 84 ×

=

x = 3360420

x =

Therefore, the value of x is 8.

4. The compound ratio of 3:4 and the inverse ratio of 4:5 is 45:x. Find x.

Solution:

The inverse ratio of 4:5 is .

The compound ratio of 3 : 4 and 5 : 4 is (3 × 5) : (4 × 4) = : .

We are given that this compound ratio is equal to 45 : x. Therefore:

15 : 16 = 45 : x

We can set up a proportion:

= 45x

Cross-multiply:

15x = 45 × 16

15x =

x = 72015

x =

Therefore, the value of x is 48.

5. In a primary school there shall be 3 teachers to 60 students. If there are 400 students enrolled in the school, how many teachers should be there in the school in the same ratio?

Solution:

The ratio of teachers to students is 3 : 60, which can be simplified to 1:20 (by dividing both sides by 3).

This means for every students, there is teacher.

If there are 400 students, we can set up a proportion to find the number of teachers (let's call it 'x'):

120 = x400

Cross-multiply:

=

x = 40020

x =

Therefore, there should be teachers in the school.

6. In the adjacent ΔABC, write all possible ratios by taking measures of sides pair wise.

(Hint : Ratio of AB : BC = 8 : 6)

Solution:

Given the side lengths AB = 8, BC = 6, and AC = 10 (though AC isn't explicitly used in the ratios, it's good to note we have a 3-4-5 triangle scaled by 2).

We can form the following ratios by taking the sides pairwise, expressed as fractions:

ABBC = 86 =

ABAC = 810 =

BCAB = 68 =

BCAC = 610 =

ACAB = 108 =

ACBC = 106 =

7. If 9 out of 24 students scored below 75% marks in a test. Find the ratio of students who scored below 75% marks to the students who scored 75% and above marks.

Solution:

Students scoring below 75% marks:

Total students:

Students scoring 75% and above marks: - =

Ratio of students scoring below 75% to students scoring 75% and above:

We can simplify this ratio by dividing both sides by their greatest common divisor, which is .

9:15 = () : () =

Therefore, the required ratio is 3:5.

8. Find the ratio of the number of vowels in the word 'MISSISSIPPI' to the number of consonants in the simplest form.

Solution:

The word MISSISSIPPI has letters.

Vowels: I, I, I, I ( vowels)

Consonants: M, S, S, S, S, P, P ( consonants)

Ratio of vowels to consonants: :

Since 4 and 7 have no common factors other than 1, the ratio is already in its simplest form.

Therefore, the ratio of vowels to consonants is 4:7.

9. Rajendra and Rehana own a business. Rehana receives 25% of the profit each month. If Rehana received ₹2080 in a particular month, what is the total profit in that month?

Solution:

Let the total profit in that month be 'P'.

Rehana receives 25% of the profit, which is equal to ₹.

We can express this as an equation:

25% of P = ₹ 2080

× P = ₹2080

× P = ₹2080

P = ₹ 20800.25

P = ₹

Therefore, the total profit in that month was ₹8320.

10. In triangle ABC, AB = 2.2 cm, BC = 1.5 cm and AC = 2.3 cm. In triangle XYZ, XY = 4.4 cm, YZ = 3 cm and XZ = 4.6 cm. Find the ratio AB : XY, BC : YZ, AC : XZ. Are the lengths of corresponding sides of ΔABC and ΔXYZ in proportion?

Solution:

Ratio AB : XY = 2.2 cm : 4.4 cm = 2244 = or

Ratio BC : YZ = 1.5 cm : 3 cm = 1530 = or

Ratio AC : XZ = 2.3 cm : 4.6 cm = 2346 = or

Since all the corresponding sides have the same ratio (1:2), the lengths of the corresponding sides of ΔABC and ΔXYZ in proportion.

Therefore, the answer is .

11. Madhuri went to a super market. The price changes are as follows. The price of rice reduced by 5% jam and fruits reduced by 8% and oil and dal increased by 10%. Help Madhuri to find the changed prices in the given table.

ItemOriginal Price/KgChanged Price
Rice₹ 30
Jam₹ 100
Apples₹ 280
Oil₹ 120
Dal₹ 80

Solution:

Rice: Reduced by 5%. Changed price = ₹ - × ₹ = ₹ - ₹ = ₹

Jam: Reduced by 8%. Changed price = ₹ - × ₹ = ₹ - ₹ = ₹

Apples: Reduced by 8%. Changed price = ₹ - × ₹ = ₹ - ₹ = ₹

Oil: Increased by 10%. Changed price = ₹ + × ₹ = ₹ + ₹ = ₹

Dal: Increased by 10%. Changed price = ₹ + × ₹ = ₹ + ₹ = ₹

12. There were 2075 members enrolled in the club during last year. This year enrolment decreased by 4%.

(a). Find the decrease in enrolment.

Solution:

Decrease in enrolment = 4 % of 2075 = 4100 × 2075 = × 2075

=

Therefore, the decrease in enrolment is 83 members.

(b) How many members are enrolled during this year?

Solution:

Members enrolled last year:

Decrease in enrolment:

Members enrolled this year: Members enrolled last year - Decrease in enrolment

= 2075 - 83

=

Therefore, 1992 members are enrolled during this year.

13. A farmer obtained a yielding of 1720 bags of cotton last year. This year she expects her crop to be 20% more. How many bags of cotton does she expect this year?

Solution:

Increase in yield = 20 % of 1720 bags

= 20100 × 1720

= × 1720

= bags

Expected yield this year = Last year's yield + Increase in yield

= bags + bags

= bags

Therefore, the farmer expects to yield 2064 bags this year.

14. Points P and Q are both on the line segment AB and on the same s> ide of its m> idpoint. P div> ides AB in the ratio 2:3, and Q div> ides AB in the ratio 3:4. If PQ = 2, then find the length of the line segment AB.

Solution:

Let the length of AB be 'x'.

Point P: APPB = 23. This means AP = x and PB = x.

Point Q: AQQB = 34. This means AQ = x and QB = x.

Since P and Q are on the same side of the midpoint, and the ratios indicate P is closer to A than Q is, we know that AP AQ.

Therefore, PQ = - .

PQ = 37x - 25x

2 = (15x - 14x)/

2 =

x = 2 ×

x =

Therefore, the length of the line segment AB is 70 units.