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    Questions Implemented using Suitable Components -Exercise 4.1

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6th class > > Questions Implemented using Suitable Components -Exercise 4.1

Questions Implemented using Suitable Components -Exercise 4.1

Question 1

x + 3 = 0   x = 3
x + 3 = 0   x = 0
x + 3 = 0   x = – 3
x – 7 = 1   x = 7
x – 7 = 1   x = 8
5x = 25     x = 0
5x = 25     x = 5
5x = 25     x = – 5
m3=2 m = – 6
m3=2 m = 0
m3=2 m = 6
Yes
No

Question 2

Check whether the value given in the brackets is a solution to the given equation or not

Question 3

Solve the following equations by trial and error method

question :5p+2=17
let p=1 then 5 x 1 +2 =
let p=2 then 5 x 2 +2 =
let p=3 then 5 x 3 +2 =
Equation is satisfied when p=3
Therefore, p = 3
question :3m-14=4
let m=1 then 3 x 1 -14 =
let m=2 then 3 x 2 -14 =
let m=3 then 3 x 3 -14 =
let m=4 then 3 x 4 -14 =
let m=3 then 3 x 5 -14 =
let m=3 then 3 x 6 -14 =
Equation is satisfied when m=4
Therefore, m = 4

Question 4

Write equations for the following statements:

Question 5

Write the following equations in statement forms:

p + 4 = 15
m – 7 = 3
2m = 7
m/5 = 3
3m/5 = 6
3p + 4 = 25
4p – 2 = 18
p/2 + 2 = 8
Twice of m is 7
Adding 2 to half of p is 8
three fifth of m is 6
4 added to three times p is 25
Subtract 7 from m to get 3
one-fifth of m is 3
Subtracting 2 from 4 times p is 18
The sum of P and 4 is 15

Question 6

Set up an equation in the following cases:

(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. (Take m to be the number of Parmit’s marbles.)

Solution: Given: 7 more than five times Permit's marbles=Irfan's marbles=37 Permit's marbles=

+ x m =37

5m+7=37

(ii) Laxmi’s father is 49 years old. He is 4 years older than three times Laxmi’s age. (Take Laxmi’s age to be y years.)

Solution:

Given: 4 years older than three times Laxmi's age=Laxmi's father age=49

Laxmi's age=

+ x y =49

3y+4=49

(iii) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. (Take the lowest score to be l.)

Solution:

Given: twice the lowest marks plus 7=highest marks=87

lowest marks=

l + =87

2l+7=87

(iv) In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be b in degrees. Remember that the sum of angles of a triangle is 180 degrees).

Solution:

Given: Iscocelese triangle

Vertex angle is twice either base angle.

Base angle=

base angle1=base angle2=b;Vertex angle=b

Sum of all angles=180o

+ +2 x = 180o

4b=180o