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    Questions Implemented using Suitable Components -Exercise 4.1

    Exercise 4.3

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6th class > > Exercise 4.3

Exercise 4.3

Question 1

Add 4 to eight times a number; you get 60.
Let the number be x.
From the question we know, 8 x +4 = 60
Upon subtracting and dividing by on both sides and solving we get , x= 7.
Therefore, x = 7.
One-fifth of a number minus 4 gives 3.
Let the number be x.
From the question we know, 1/5 of x-4=3
Upon adding and then multiplying by 5 on both sides and solving we get , x= 35.
Therefore, x = 35.
If I take three-fourths of a number and add 3 to it, I get 21.
Let the number be x .
From the question we know, 3/4 of x +3=21
Upon subtracting and then multiplying by 4/3 on both sides and solving we get , x = 24.
Therefore, x = 24.
When I subtracted 11 from twice a number, the result was 15.
Let the number be x .
From the question we know, 2 x -11=15
Upon adding and then dividing by on both sides and solving we get , x =13 .
Therefore, x = 13.
Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.
Let the number be x.
From the question we know, 3 x-50=8
Upon adding and then dividing by on both sides and solving we get , x=19 .
Therefore, x = 19.
Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.
Let the number be x.
From the question we know, x+19/5=8
Upon subtracting on both sides and solving we get , x=45 .
Therefore, x = 45.
Anwar thinks of a number. If he takes away 7 from 52of the number, the result is 23.
Let the number be x.
From the question we know, 52 of x-7 =23
Upon adding and then dividing by on both sides and solving we get , x= 12 .
Therefore, x = 12 .

Question 2

(a) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?

Solution:

let lowest score be l

Given: twice the lowest score +7=highest mark

x l + 7=

To isolate l subtract on both sides

2l+7-7=87-7;2l=

Divide by on both the sides

l=40

(b) In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180°).

Solution:

let base angle 1 = base angle 2 = b

Given: vertex angle=40o

b+b+ =

To isolate b subtract on both sides

2b+40-40=180-40;2b=

Divide by on both the sides

b=

(c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?

Solution:

let Rahul runs be r

Given: Sachin score = 2r

r+2r= -

3r =

Divide by on both the sides

r =

Question 3

  1. Solve the following: (i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?

Solution:

let Parmit's marbles be m

Given: 5 x Parmit's marbles+7= Irfan's marbles=37

m+=37

To isolate m subtract on both sides

5m+7-7=37-7;5m=

Divide by on both the sides

m=

(ii) Laxmi’s father is 49 years old. He is 4 years older than three times Laxmi’s age. What is Laxmi's age?

Solution:

Let Laxmi's age=m

Given: 3 x Laxmi's age +4 =Laxmi's father age=49

x m + =49

To isolate m subtract on both sides

3m+4-4=49-4;3m=

Divide by on both the sides

m=

(iii) People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?

Let Fruit trees=F

Given: 3 x Fruit trees +2 =Non-fruit trees=77

x F + =77

To isolate F subtract on both sides

3F+2-2=77-2;3F=

Divide by on both the sides

F=

Question 4

Solve the following riddle: I am a number, Tell my identity! Take me seven times over And add a fifty! To reach a triple century You still need forty!

Letthenumberben

  • Now, multiply it 7 times (Step 1)
  • add fifty (Step 2)
  • reach triple century need 40 = -40=(Step 3)
  • Subtract by on both sides (Step 3)
  • Divide by on both sides
  • n=30
  • thus,n=30