Subtraction of Decimals
Can you now subtract 2.58 and 1.32?
Mark 2.58 in this square by putting dots of
Mark 1.32 in this square by putting dots of
This can be shown by the table.
| Ones | Tenths | Hundredths |
|---|---|---|
| 2 | 5 | 8 |
| 1 | 3 | 2 |
Thus, 2.58 - 1.32 =
Therefore, we can say that, subtraction of decimals can be done by subtracting hundredths from hundredths, tenths from tenths, ones from ones and so on, just as we did in addition.
Sometimes while subtracting decimals, we may need to regroup like we did in addition.
Let us subtract 1.74 from 3.5.
Mark 1.74 in this square by putting dots of
Mark 3.5 in this square by putting dots of
| Ones | Tenths | Hundredths |
|---|---|---|
| 3 | 5 | 0 |
| 1 | 7 | 4 |
Subtract in the hundredth place. Can’t subtract! Borrow from the tenth place.
Thus, 3.5 – 1.74 =
Subtract 1.85 from 5.46.
Mark 1.85 in this square by putting dots of
Mark 5.46 in this square by putting dots of
| Ones | Tenths | Hundredths |
|---|---|---|
| 5 | 4 | 6 |
| 1 | 8 | 5 |
Subtract in the hundredth place. Can’t subtract! Borrow from the tenth place.
Thus, 5.46 – 1.85 =
Subtract 5.25 from 8.28.
Mark 5.25 in this square by putting dots of
Mark 8.28 in this square by putting dots of
| Ones | Tenths | Hundredths |
|---|---|---|
| 8 | 2 | 8 |
| 5 | 2 | 5 |
Subtract in the hundredth place. Can’t subtract! Borrow from the tenth place.
Thus, 8.28 – 5.25 =
Subtract 0.95 from 2.29.
Mark 0.95 in this square by putting dots of
Mark 2.29 in this square by putting dots of
| Ones | Tenths | Hundredths |
|---|---|---|
| 2 | 2 | 9 |
| 0 | 9 | 5 |
Subtract in the hundredth place. Can’t subtract! Borrow from the tenth place.
Thus, 2.29 – 0.95 =
Subtract 2.25 from 5.68.
Mark 2.25 in this square by putting dots of
Mark 5.68 in this square by putting dots of
| Ones | Tenths | Hundredths |
|---|---|---|
| 5 | 6 | 8 |
| 2 | 2 | 5 |
Subtract in the hundredth place. Can’t subtract! Borrow from the tenth place.
Thus, 5.68 – 2.25 =
Abhishek had ₹ 7.45. He bought toffees for ₹ 5.30. Find the balance amount left with Abhishek.
Urmila’s school is at a distance of 5 km 350 m from her house. She travels 1 km 70 m on foot and the rest by bus. How much distance does she travel by bus?
- Total distance of school from the house =
km m - Convert the m into km
km - Distance travelled on foot =
km m - Convert the m into km
km - subtraction of two numbers
- We get the answer is =
m - Thus, distance travelled by bus = 4.280 km or 4 km 280 m
Kanchan bought a watermelon weighing 5 kg 200 g. Out of this she gave 2 kg 750 g to her neighbour. What is the weight of the watermelon left with Kanchan?
- Total weight of the watermelon =
kg g - Convert the g into kg =
kg - Watermelon given to the neighbour =
kg g - Convert the g into kg =
kg - subtraction of two numbers
- Hence,we get the answer is
kg - Therefore, weight of the remaining watermelon = 2.450 kg