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Chapter 3: Polynomials > What are Polynomials?

What are Polynomials?

A polynomial in the variable x is an algebraic expression consisting of one or more terms, where each term is of the form axn.

Here: 1. a is a real number (coefficient) where a 0 .

2. n is a number (non-negative integer: 0, 1, 2, 3, ...).

A polynomial can have multiple terms added or subtracted, but it must not contain:

1. Negative exponents (e.g: x1, x2).

2. Fractional exponents (e.g: x12, x34).

3. Variables in the denominator (e.g: 1x , 4x+2)

Examples of Polynomials and Non-Polynomials

PolynomialsNot Polynomials
2x4x12
13x - 43x2 + 4x1+5
x2 - 2x - 14 + 1x

Why is 1y1 not a polynomial?

  • The denominator contains a variable (y-1) , which introduces division by a variable.

  • A polynomial have variables in the denominator.

Now, look at the polynomial px = 3x74x6+x+9.

What is the term with the highest power of x? It is . The exponent of x in this term is .

Similarly, in the polynomial q(y)= 5y64y26, the term with the highest power of y is and the exponent of y in this term is .

We call the highest power of the variable in a polynomial as the degree of the polynomial. So, the degree of the polynomial 3x7-4x6+ x + 9 is 7 and the degree of the polynomial 5y6 -4y2-6. The degree of a non-zero constant polynomial is zero.

Example

Find the degree of each of the polynomials given below:

Instructions

(i)x5-x4 + 3
The highest power of the variable is . So, the degree of the polynomial is .
(ii) 2- y2- y3 + 2y8
The highest power of the variable is . So, the degree of the polynomial is .
(iii) 2
The only term here is 2 which can be written as .So the exponent of x is . Therefore, the degree of the polynomial is .

Now observe the polynomials p(x) = 4x+5, q(y) = 2y, r(t) = t + 2 and s(u) = 3u. Do you see anything common among all of them?

The degree of each of these polynomials is .

A polynomial of degree one is called a polynomial.

Some more linear polynomials in one variable are 2x1, 2y+1, 2u. Now, try and find a linear polynomial in x with 3 terms? You would not be able to find it because a linear polynomial in x can have at most two terms.

So, any linear polynomial in x will be of the form ax + b, where a and b are constants and a ≠ 0.

Similarly, ay + b is a linear polynomial in y.

Now consider the polynomials : 2x2 + 5, 5x2 + 3x , x2 and x2 + 25 x.

Do you agree that they are all of degree two? A polynomial of degree two is called a polynomial.

If you observe any quadratic polynomial in x then it is of the form ax2+ bx + c ,where a ≠ 0 and a, b, c are constants.

Similarly, quadratic polynomial in y will be of the form ay2+ by + c, provided a ≠ 0 and a, b, c are constants.

We call a polynomial of degree : a cubic polynomial. Some examples of a cubic polynomial in x are 4x3,2x3+1,5x3+x2,6x3-x,6-x3,2x3+4x2+6x+7

How many terms do you think a cubic polynomial in one variable can have?

It can have at most terms. These may be written in the form ax3+ bx2 + cx + d, where a ≠ 0 and a, b, c and d are constants.

Instructions

A polynomial function p(x) takes different values depending on the input x . To find the value of a polynomial at a given x , simply substitute that value into the expression.

Example

Consider the polynomial: p(x) = x2 - 2x - 3

To find the value of p(x) at x = 1 : p(1) = 12 - 2(1) - 3

= 1 - 2 - 3 =

Thus, the value of p(x) at x = 1 is .

Similarly, for x = 0 : p(0) = 02 - 2(0) - 3

= 0 - 0 - 3 =

So, p(0) = .

Zeroes of a Polynomial

Consider the polynomial p(x) = 5x3-2x2 + 3x-2

Instructions

5x32x2+3x2

  • If we replace x by 1 everywhere in p(x), we get
  • calculate the terms
  • Therfore, p(1) =
  • Also find the p(0) =
  • calculate the terms
  • Therfore, p(0) =

Example 2

Find the value of each of the following polynomials at the indicated value of variables:

(i) p(x) = 5x2-3x+7 at x = 1

Instructions

5x23x+7

  • The value of the polynomial p(x) at x = 1 is given by
  • calculate the terms
  • Therfore, p(x) =
  • We have found the answer.

(ii) q(y) = 3y34y+11 at y = 2

Instructions

3y34y+11

  • The value of the polynomial q(y) at y = 2 is given by
  • calculate the terms
  • Therfore, q(y) = +
  • We have found the answer.

(iii) p(t) = 4t4+5t3t2+6 at t = a

Instructions

4t4+5t3t2+6

  • The value of the polynomial p(t) at t = a is given by
  • Calculating the terms, we get: p(a) = + a3 + + 6.
  • We have found the answer.

Now, consider the polynomial p(x) = x – 1.

What is p(1)? Note that : p(1) = 1 – 1 = .

As p(1) = 0, we say that 1 is a zero of the polynomial p(x).

Similarly, you can check that 2 is a zero of q(x), where q(x) = x – 2.

In general, we say that a zero of a polynomial p(x) is a number c such that p (c) = 0. In other words,

Zeros of a Polynomial are those values when put in the polynomial instead of a variable, the result becomes zero.

You must have observed that the zero of the polynomial x – 1 is obtained by equating it to 0, i.e., x – 1 = 0, which gives x = .

We say p(x) = 0 is a polynomial equation and 1 is the root of the polynomial equation p(x) = 0. So we say 1 is the zero of the polynomial x – 1, or a root of the polynomial equation x – 1 = 0.

Now, consider the constant polynomial 5. Can you tell what its zero is ?

It has no zero of polynomial because replacing x by any number in 5x0 still gives us 5.

In fact, a non-zero constant polynomial has no zero. What about the zeroes of the zero polynomial? By convention, every real number is a zero of the zero polynomial.

Note: Do not get confused between zeroes of polynomials and zero of polynomial