Hard Level Worksheet Questions
Note: Answer each question with steps and explanation. Write down the answers on sheet and submit to the school subject teacher.
Ratio applications involve complex problem-solving scenarios including business partnerships, investment calculations, mixture problems, and proportional reasoning. These advanced concepts are essential for understanding financial mathematics, engineering calculations, and real-world analytical thinking.
Let's explore advanced ratio applications and proportional reasoning.
1. Write the ratio of 2 hours to 75 minutes in simplest form.
Step 1: Convert to same units: 2 hours =
Step 2: Ratio = 120:75, simplified by dividing by
Step 3: Simplest form =
Perfect! 2 hours = 120 minutes, so 120:75 = 8:5.
2. If ₹360 is divided between A and B in the ratio 5:7, find B's share.
Step 1: Total parts = 5 + 7 =
Step 2: B's share = (7/12) × 360 =
Excellent! B gets 7 parts out of 12 total parts.
3. Find the mean proportional between 18 and 50.
Step 1: Mean proportional = √(18 × 50) = √
Step 2: Mean proportional =
Great! Mean proportional between a and b is √(a×b) = √900 = 30.
4. Express 5 km to 250 m as a ratio in simplest form.
Step 1: Convert to same units: 5 km =
Step 2: Ratio = 5000:250, simplified by dividing by
Step 3: Simplest form =
Perfect! 5000:250 = 20:1 after dividing by 250.
5. Write the third proportional to 8 and 12.
Step 1: If a:b = b:c, then c is third proportional
Step 2: 8:12 = 12:c, so c = (12 × 12) ÷ 8 =
Excellent! Third proportional: 8:12 = 12:18.
6. Find the fourth proportional to 3, 5, and 15.
Step 1: If a:b = c:d, then d is fourth proportional
Step 2: 3:5 = 15:d, so d = (5 × 15) ÷ 3 =
Great! Fourth proportional: 3:5 = 15:25.
7. If 8 workers complete a job in 15 days, how many days will 12 workers take?
Step 1: Total work = 8 × 15 =
Step 2: Time for 12 workers = 120 ÷ 12 =
Perfect! Inverse proportion: more workers means less time.
8. Find the cost of 15 pens if the cost of 8 pens is ₹120.
Step 1: Cost per pen = ₹120 ÷ 8 =
Step 2: Cost of 15 pens = 15 × ₹15 =
Excellent! Using unit rate method: ₹15 per pen.
Drag each problem to its correct application type:
Part B: Short Answer Questions (2 Marks Each)
1. Monthly incomes of A and B are in ratio 4:5, expenses in ratio 7:9. If each saves ₹1,500, find their incomes.
Step 1: Set up variables
Let incomes be 4x and 5x, expenses be 7y and 9y
Step 2: Set up savings equations
A's savings: 4x
B's savings: 5x
Step 3: Solve the system
From the ratio of savings and given information: x =
Step 4: Calculate incomes
A's income = 4 × 3000 =
B's income = 5 × 3000 =
Perfect! A earns ₹12,000 and B earns ₹15,000 monthly.
2. Sides of two triangles are in ratio 3:4. If smaller triangle's perimeter is 60 cm, find larger triangle's perimeter.
Step 1: Understand proportional relationship
Since corresponding sides are in ratio 3:4, perimeters are also in ratio
Step 2: Calculate larger perimeter
If smaller perimeter : larger perimeter = 3:4
Then larger perimeter = (
Excellent! Similar figures have proportional linear measurements.
3. A train covers 120 km in 2 hours. How long to cover 300 km at same speed?
Step 1: Calculate speed
Speed = Distance ÷ Time =
Step 2: Calculate time for 300 km
Time =
Great! Using speed = distance/time formula consistently.
4. Mixture contains milk and water in ratio 7:3. How much water to add to 40 litres to make ratio 3:2?
Step 1: Find initial quantities
Initial milk = (
Initial water = (
Step 2: Calculate required water for ratio 3:2
For ratio 3:2, We add x litres of water.
Milk = 28 litres.
Water becomes
Milk/Water =
28/12+x = 3/2, Where x =
Outstanding! Mixture problems require careful ratio calculations.
Part C: Long Answer Questions (4 Marks Each)
1. A and B together have ₹2,400. If 3/8 of A's amount equals 1/4 of B's amount, find each amount.
Step 1: Set up variables
Let A have ₹x, then B has ₹(
Step 2: Set up equation from given condition
(
Where x =
Step 3: Find both amounts
A has ₹960, B has ₹(2400 - 960) =
Perfect! A has ₹960 and B has ₹1,440.
2. Daily wages of two workers are in ratio 7:9. If each gets ₹9 increase, ratio becomes 8:9. Find original wages.
Step 1: Set up initial conditions
Let original wages be 7x and 9x
Step 2: Set up equation after increase
After ₹9 increase: (
New ratio: (7x + 9):(9x + 9) =
Step 3: Cross multiply and solve
Solving x =
Step 4: Find original wages
Therefore, Original wages are ₹
Great work! You carefully used ratios to trace back the original daily wages.
3. ₹84,000 distributed among P, Q, R such that P gets 4/7 of Q's share, Q gets 3/5 of R's share.
Step 1: Express in terms of R's share
Let R = x
Then Q = (
And P = (4/7) × (3/5)x = (
Step 2: Set up total equation
P + Q + R =
(12/35)x + (3/5)x + x = 84000
Solving x =
Step 3: Calculate individual shares
R gets
Q gets =
P gets =
Excellent! Complex ratio problem solved systematically.
4. A, B, C invest in ratio 3 : 4 : 5. After 6 months, A invests ₹12,000 more, B withdraws ₹8,000. Find profit shares if total profit is ₹2,10,000.
Step 1: Calculate time-weighted investments
Let initial investments be 3x, 4x, 5x
Step 2: Calculate effective capital × time
A's effective investment = 3x ×
=
B's effective investment = 4x ×
=
C's effective investment = 5x ×
So the profit-sharing ratio is proportional to
(6x + 12000) : (8x − 8000) : (10x)
Step 3: (with x = ₹8,000): Compute the ratio
A =
B =
C:
Ratio = 60,000 : 56,000 : 80,000 =
Step 4: Split the profit ₹2,10,000 in 15 : 14 : 20
Through complex calculations involving the profit distribution
Total parts = 15 + 14 + 20 =
One part = ₹2,10,000 ÷ 49 ≈
A’s share = ₹
B’s share = ₹
C’s share = ₹
Outstanding! Partnership profit sharing with mid-year changes.
Test your understanding with these multiple choice questions:
For each question, click on the correct answer:
1. The mean proportional between 25 and 100 is:
(a) 50 (b) 75 (c) 60 (d) 40
Correct! Mean proportional = √(25 × 100) = √2500 = 50.
2. The ratio 0.75 : 1.25 in simplest form is:
(a) 3:5 (b) 4:5 (c) 5:3 (d) 5:4
Correct! 0.75:1.25 = 75:125 = 3:5 (dividing by 25).
3. The third proportional to 6 and 9 is:
(a) 12 (b) 13.5 (c) 18 (d) 27
Correct! If 6:9 = 9:x, then x = (9×9)/6 = 81/6 = 13.5.
4. If 12 workers can build a wall in 15 days, 20 workers will take:
(a) 9 days (b) 10 days (c) 8 days (d) 12 days
Correct! Total work = 12×15 = 180 worker-days. So 20 workers take 180÷20 = 9 days.
5. The scale of a map is 1:2,00,000. A distance of 3 cm on the map represents:
(a) 4 km (b) 5 km (c) 6 km (d) 7 km
Correct! 3 cm × 200000 = 600000 cm = 6000 m = 6 km.
🎉 Outstanding! You've Mastered Hard Level Ratio Applications! Here's what you accomplished:
✓ Advanced Proportion Calculations: Mean proportionals, third and fourth proportionals
✓ Complex Division Problems: Multi-variable ratio distribution with constraints
✓ Investment and Partnership: Time-weighted capital calculations and profit sharing
✓ Mixture and Alligation: Changing ratios and component calculations
✓ Inverse Proportion Mastery: Work-time, speed-distance relationships
✓ Chain Ratio Problems: Multiple dependent relationships and systematic solving
✓ Scale and Map Applications: Real-world measurement and representation
✓ Financial Mathematics: Income-expense ratios, wage calculations, business scenarios
Your expertise in ratio applications prepares you for advanced business mathematics, engineering calculations, and complex analytical problem-solving!