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Simple Equations > Usage of algebraic equations in solving day to day problem

Usage of algebraic equations in solving day to day problem

The following examples demonstrate how algebraic equations can be used to solve practical, everyday problems by:

(1) Defining variables

(2) Creating equations based on given information

(3) Solving the equations step by step

(4) Interpreting the results in the context of the original problem

Example 1: Age and Family Composition

Sarah is 25 years older than her younger brother. In 5 years, the sum of their ages will be 50.

Let x = younger brother's current age

Then = Sarah's current age

In 5 years: x + and (x + 25) +

Equation: (x + 5) + (x + ) =

Solving: x + =

x =

So the younger brother is currently 7.5 years old, and Sarah is years old.

Example 2: Rectangle Dimensions

A rectangle's length is 3m more than its width. If the perimeter is 34m, we can find its dimensions:

Let width = x

Length = x +

Perimeter equation: 2(x + (x + 3)) = 34

Solving: 2(2x + 3) = 34

+ = 34

x =

Width is 7 m, length is m.

Example 3: Workforce Composition

In a factory, there are 45 workers. The number of female workers is 5 less than male workers. How many female and male workers are there?

Let x = number of female workers

Male workers = x +

Total workers equation: x + (x + 5) =

Solving: 2x + 5 = 45

x =

Female workers:

Male workers: