Exercise 6.2
1. Find the square root of the following numbers by Prime factorization method.
(i) 441
Solution:
Prime factors of 441:
Pair the prime factors: (3 × 3) × (7 × 7)
Take one factor from each pair: 3 × 7
Multiply the factors: 3 × 7 =
Therefore, the square root of 441 is
(ii) 784
Solution:
Prime factors of 784:
Pair the prime factors: (2 × 2) × (2 × 2) × (7 × 7)
Take one factor from each pair: 2 × 2 × 7
Multiply the factors: 2 × 2 × 7 =
Therefore, the square root of 784 is
(iii) 4096
Solution:
Prime factors of 4096:
Pair the prime factors: (2 × 2) × (2 × 2) × (2 × 2) × (2 × 2) × (2 × 2) × (2 × 2)
Take one factor from each pair: 2 × 2 × 2 × 2 × 2 × 2
Multiply the factors: 2 × 2 × 2 × 2 × 2 × 2 =
Therefore, the square root of 4096 is
(iv) 7056
Solution:
Prime factors of 7056:
Pair the prime factors: (2 × 2) × (2 × 2) × (3 × 3) × (7 × 7)
Take one factor from each pair: 2 × 2 × 3 × 7
Multiply the factors: 2 × 2 × 3 × 7 =
Therefore, the square root of 7056 is
2. Find the smallest number by which 3645 must be multiplied to get a perfect square.
Solution:
Prime factorize 3645:
To make it a perfect square, each prime factor must have an
The smallest number to multiply is 3 × 5 =
3. Find the smallest number by which 2400 is to be multiplied to get a perfect square and also find the square root of the resulting number.
Solution:
Prime factorize 2400:
To make it a perfect square, we need one more 2 and one more 3.
The smallest number to multiply is 2 × 3 =
The resulting number is 2400 × 6 =
The square root of 14400 is
4. Find the smallest number by which 7776 is to be divided to get a perfect square.
Solution:
Prime factorize 7776: 7776 =
To make it a perfect square by division, we need to remove the extra factors so that all powers are
We can divide by 2 × 3 =
The smallest number to divide by is
5. 1521 trees are planted in a garden in such a way that there are as many trees in each row as there are rows in the garden. Find the number of rows and number of trees in each row.
Solution:
Let 'x' be the number of rows and also the number of trees in each row.
Total trees = x × x =
Find the square root of 1521:
1521 =
x =
Therefore, there are
6. A school collected ₹2601 as fees from its students. If fee paid by each student and number students in the school were equal, how many students were there in the school?
Solution:
Let 'x' be the number of students and also the fee paid by each student.
Total fee collected =
Find the square root of 2601:
2601 =
x =
Therefore, there were 51 students in the school.
7. The product of two numbers is 1296. If one number is 16 times the other, find the two numbers?
Solution:
Let one number be 'x'. Then the other number is
Product = x × 16x =
x =
The two numbers are
8. 7921 soldiers sat in an auditorium in such a way that there are as many soldiers in a row as there are rows in the auditorium. How many rows are there in the auditorium?
Solution:
Let 'x' be the number of rows and also the number of soldiers in each row.
Total soldiers = x × x =
Find the square root of 7921: 7921 =
x =
Therefore, there are 89 rows in the auditorium.
9. The area of a square field is 5184 m². Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth.
Solution:
Side of the square field =
Perimeter of the square field =
Let the breadth of the rectangular field be 'b'. Then the length is
Perimeter of the rectangular field = 2(l + b) = 2(
b =
Length of the rectangular field =
Area of the rectangular field = length × breadth = 96 × 48 =