Finding Square Root by Division Method
Finding square root by division method
When the numbers are large, even the method of finding square root by prime factorisation becomes lengthy and difficult. To overcome this problem we use Long Division Method.
For this we need to determine the number of digits in the square root. See the following table:
| Number | Square | Property |
|---|---|---|
| 10 | 100 | which is the smallest |
| 31 | 961 | which is the greatest |
| 32 | 1024 | which is the smallest |
| 99 | 9801 | which is the greatest |
So, what can we say about the number of digits in the square root if a perfect square is a 3-digit or a 4-digit number? We can say that, if a perfect square is a 3-digit or a 4-digit number, then its square root will have
Can you tell the number of digits in the square root of a 5-digit or a 6-digit perfect square?
- The smallest 5-digit perfect square is
10000 which gives =10000 while the largest 5-digit perfect square is 99856 which gives =99856 - This tells us that the square root has
digits. - Checking for 6-digit perfect square: we have
100489 which gives =100489 which is the smallest perfect square while the largest 5-digit perfect square is 998001 which gives =998001 - This tells us that in this case as well, the square root has
digits. - Thus, the square root of 5 (or) 6-digit perfect square has a total of 3 digits.
The smallest 3-digit perfect square number is 100 which is the square of 10 and the greatest 3-digit perfect square number is 961 which is the square of 31. The smallest 4-digit square number is 1024 which is the square of 32 and the greatest 4-digit number is 9801 which is the square of 99.
Think Discuss and Write
Can we say that if a perfect square is of n-digits, then its square root will have
The relationship between the number of digits in a perfect square and the number of digits in its square root follows a specific pattern, but it does not fit perfectly into the formulas
If n is even: A perfect square with
Example:
10000 (a 5-digit perfect square) has
1000000 (a 7-digit perfect square) has
If n is odd:
A perfect square with n digits typically has
The formula you suggested is generally correct but can be considered an approximation. The exact number of digits can vary slightly depending on the specific numbers involved.
The use of the number of digits in square root of a number is useful in the following method: Consider the following steps to find the square root of 529.
- Starting from right place a bar on top of every pair of digits. If a single digit remains on the left, add a bar to that as well. For eg: 5 29
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 5 <2 2 ). Here, 2 becomes the first digit of the quotient and we get a remainder of3 2 when subtracting from 5.2 2 - Bring down the number under the next bar (i.e. 29) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 4_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- As
× 3 = 129, we can choose the digit to be filled in the blank as . - Since, the remainder is
and there are no more digits left in the given number, we get: =529 - We have found the square root of 529.
Now consider
- Place a bar over every pair of digits starting from the one’s digit. (40 96)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 40 <6 2 ). Here, 6 becomes the first digit of the quotient and we get a remainder of7 2 when subtracting from 40.6 2 - Bring down the number under the next bar (i.e. 96) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 12_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 124 ×
= 496 - Since, the remainder is
and there are no more digits left in the given number, we get: =4096 . - We have found the square root of 4096.
Estimating the number
We use bars to find the number of digits in the square root of a perfect square number.
= 23 and = 64
In both the numbers 529 and 4096 there are two bars and the number of digits in their square root is
Can you tell the number of digits in the square root of 14400 ? By placing bars on top of , we get
Thus, the square root will be having 3 digits.
Without calculating square roots, find the number of digits in the square root of the following numbers.
Example 9: Find the square root of:
(i) 729
- Place a bar over every pair of digits starting from the one’s digit. (7 29)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 7 <2 2 ). Here, 2 becomes the first digit of the quotient and we get a remainder of3 2 when subtracting from 7.2 2 - Bring down the number under the next bar (i.e. 29) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 4_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 47 ×
= 329. - Since, the remainder is
and there are no more digits left in the given number, we get: =729 . - We have found the square root of 729.
(ii) 1296
- Place a bar over every pair of digits starting from the one’s digit. (12 96)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 12 <3 2 ). Here, 3 becomes the first digit of the quotient and we get a remainder of4 2 when subtracting from 12.3 2 - Bring down the number under the next bar (i.e. 96) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 6_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 66 ×
= 396 - Since, the remainder is
and there are no more digits left in the given number, we get: =1296 . - We have found the square root of 1296.
Example 10: Find the least number that must be subtracted from 5607 so as to get a perfect square. Also find the square root of the perfect square.
- Place a bar over every pair of digits starting from the one’s digit. (56 07)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 56 <7 2 ). Here, 7 becomes the first digit of the quotient and we get a remainder of8 2 when subtracting from 56.7 2 - Bring down the number under the next bar (i.e.076) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 14_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 144 ×
= 576 - Since, the remainder is
and quotient is . Thus 74 2 5607. - Thus, the least number that must be subtracted from 5607 to get a perfect square:
.
Example 11: Find the greatest 4-digit number which is a perfect square.
- Let's take the greatest 4-digit number i.e.
- Place a bar over every pair of digits starting from the one’s digit. (99 99)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 99 <9 2 ). Here, 9 becomes the first digit of the quotient and we get a remainder of10 2 when subtracting from 99.9 2 - Bring down the number under the next bar (i.e. 99) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 18_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 189 ×
= 1701 - Since, the remainder is
and there are no more digits left in the given number, we can say that we need to subtract from in order to get the largest four-digit perfect square. Thus, the answer is - We also find that
=9801 .
Example 12: Find the least number that must be added to 1300 so as to get a perfect square. Also find the square root of the perfect square.
- Place a bar over every pair of digits starting from the one’s digit. (13 00)
- From the left, find the square which is less than or equal to the digit. Here we have, (
< 13 <3 2 ). Here, 3 becomes the first digit of the quotient and we get a remainder of4 2 when subtracting from 13.3 2 - Bring down the number under the next bar (i.e. 00) to the right of the remainder. We now get the new dividend i.e.
- In the divisor put the first digit as double the quotient and place a blank its right. i.e. 6_
- Put the largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend.
- We get that: 66 ×
= 396 - Since, the remainder is
and there are no more digits left in the given number. - Thus, we have
as our quotient which tells us that < 1300. We know that36 2 =37 2 . - Thus, the least number that must be added to 1300 so as to get a perfect square: 1369 - 1300 =
.