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Geometrical Constructions > Moderate Level Worksheet

Moderate Level Worksheet

Very Short Answer Questions (1 Mark Each)

(1) State the SAS criterion for constructing a triangle.

SAS construction requires and the between them.

Correct! SAS = Side-Angle-Side with the angle between the two given sides.

(2) Which triangle construction method uses two angles and one side?

The method uses two angles and one side.

Perfect! ASA = Angle-Side-Angle construction method.

(3) Name the instrument used to measure angles directly.

A is used to measure angles directly.

Excellent! Though in pure constructions, we avoid using protractors.

(4) Write the steps to construct a 90° angle using only a compass.

(5) Define locus of points equidistant from two fixed points.

The locus is the of the the two points.

Perfect! Every point on this locus is equidistant from both fixed points.

Short Answer Questions (2 Marks Each)

Note: Answer each question with complete construction steps and justifications and submit to subject teacher.

(1) Construct a triangle given base 5 cm, one adjacent angle 60°, and other adjacent side 6 cm.

(2) Construct a triangle similar to a given triangle with scale factor 32.

(3) Construct a perpendicular bisector of a line segment and justify why it is perpendicular.

(4) Construct a triangle given base 6 cm, base angle 45°, and sum of other two sides 8 cm.

(5) Construct a triangle with sides 4 cm, 5 cm, and 6 cm using SSS method.

Long Answer Questions (4 Marks Each)

Note: Answer each question with complete construction steps and justifications and submit to subject teacher.

(1) Construct a triangle whose sides are 6 cm, 8 cm, and 10 cm, and then construct a similar triangle with scale factor 2/3.

(2) Construct a triangle with base 6 cm, base angle 60°, and difference of other two sides 2 cm.

(3) Construct a right triangle with base 5 cm and hypotenuse 13 cm.

(4) Construct a triangle ABC in which AB = 4 cm, BC = 5 cm, AC = 6 cm, and then construct another triangle similar to it with scale factor 32.

(5) Construct a tangent to a circle of radius 4 cm from a point 7 cm away from its center.

Part B: Objective Questions (1 Mark Each)

Choose the correct answer and write the option (a/b/c/d)

(1) Constructing a triangle given two sides and included angle is:

(a) SAS method (b) SSS method (c) ASA method (d) RHS method

SAS method
SSS method
ASA method
RHS method

Correct! SAS = Side-Angle-Side with the included angle.

(2) Constructing a triangle given two angles and one side is:

(a) ASA method (b) SAS method (c) SSS method (d) AAA method

ASA method
SAS method
SSS method
AAA method

Correct! ASA = Angle-Side-Angle construction method.

(3) A perpendicular bisector always:

(a) Passes through midpoint (b) Is parallel to line (c) Divides line into unequal parts (d) Bisects an angle

Passes through midpoint
Is parallel to line
Divides line into unequal parts
Bisects an angle

Correct! Perpendicular bisector passes through midpoint at 90°.

(4) In constructing a tangent from an external point to a circle, which theorem is applied?

(a) Pythagoras theorem (b) Thales theorem (c) Midpoint theorem (d) Basic proportionality theorem

Pythagoras theorem
Thales theorem
Midpoint theorem
Basic proportionality theorem

Correct! Thales theorem: angle in semicircle is 90°.

(5) The scale factor less than 1 gives:

(a) Smaller similar triangle (b) Bigger similar triangle (c) Equal triangle (d) No triangle

Smaller similar triangle
Bigger similar triangle
Equal triangle
No triangle

Correct! Scale factor < 1 reduces the size of the triangle.

(6) To construct a triangle when three sides are known, we use:

(a) SSS construction (b) SAS construction (c) ASA construction (d) RHS construction

SSS construction
SAS construction
ASA construction
RHS construction

Correct! SSS = Side-Side-Side construction for three known sides.

(7) The difference of two sides of a triangle is given in:

(a) Special construction problems (b) SSS construction (c) ASA construction (d) RHS construction

Special construction problems
SSS construction
ASA construction
RHS construction

Correct! Sum or difference problems require special construction techniques.

(8) Constructing a tangent to a circle uses:

(a) Compass and ruler (b) Protractor only (c) Ruler only (d) Calculator

Compass and ruler
Protractor only
Ruler only
Calculator

Correct! All geometric constructions use only compass and ruler.

(9) A right triangle can be constructed using:

(a) RHS condition (b) SSS condition (c) ASA condition (d) AAA condition

RHS condition
SSS condition
ASA condition
AAA condition

Correct! RHS = Right angle-Hypotenuse-Side for right triangles.

(10) The bisector of an angle divides the angle into:

(a) Two equal angles (b) Two complementary angles (c) Two supplementary angles (d) Unequal parts

Two equal angles
Two complementary angles
Two supplementary angles
Unequal parts

Correct! Bisector divides an angle into two equal parts.

Two angles and one side
Right angle, hypotenuse, side
Two sides and included angle
Angle-Side-Angle
Three sides given
Side-Angle-Side
Side-Side-Side
Right triangle construction
SAS Method
ASA Method
SSS Method
RHS Method

Construction Methods Challenge

Determine whether these statements are True or False:

SAS uses two sides and included angle
Scale factor > 1 gives smaller triangle
Tangent construction uses Thales theorem
SSS construction needs three sides
ASA method uses three angles
Perpendicular bisector passes through midpoint

Construction Methods Quiz