Tangents of a Circle
In the previous section, we have seen that a tangent to a circle is a line that intersects the circle at only
To understand the existence of the tangent to a circle at a point, let us perform the following activities:
Activity 1 : Drag the two point of the red line in different ways and check for the intersection points between the line and the circle. What can be observed?
Only in one position, you will see that it will intersect the circle at only one point (say, P). For all the rest of the cases, there are
So, we can conclude that there is only
In other words:
The tangent to a circle is a special case of the secant, when the two end points of its corresponding chord
Activity 2 : Connect the points in the figure below.
When you from the first line to the last you observe that the length of the chord cut by the lines slowly increases and then starts decreasing as you cross the center. In one case, it is zero at the start and in another case, it becomes zero on the other side of the circle. These are the tangents to the circle parallel to the given secant
We can see that there cannot be more than
The common point of the tangent and the circle is called the point of contact and the tangent is said to touch the circle at the
Here is a wheel with diameter. Move the circle and observe where it touches the ground.
Do you see any tangent anywhere? In fact, the wheel moves along a line which is a tangent to the circle representing the
As you drag the wheel along the ground you see that the wheel spokes seem to be at
This is true for all other points in the circle too. That is, we notice that in all positions, the radius through the point of contact with the ground appears to be at right angles to the tangent. We shall now prove this property of the tangent.
The tangent at any point of a circle is perpendicular to the radius through the point of contact.
Proof:
Given: Circle with centre O
Line XY- tangent to the circle at a point P
To be proved: OP ⊥ XY.
Construction: Take a point Q on XY other than P and join OQ
Note: The point Q must lie outside the circle, else XY will become a secant and not a tangent to the circle.
Let OQ touch circle at R. Then OQ =
But OR =
as OR = OP = Radius of the circle.
OQ = OR + RQ
Since this happens for every point on the line XY except the point P,
So OP ⊥
1. By theorem above, we can also conclude that at any point on a circle there can be one and only one tangent.
2. The line containing the radius through the point of contact is also sometimes called the ‘normal’ to the circle at the point.