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Chapter 13: Visualising 3D in 2D > Exercise 13.2

Exercise 13.2

1.Count the number of faces , vertices , and edges of given polyhedra and verify Euler’s formula.

i.

Solution

Triangular Prism Analysis

Faces (F):

triangular faces

rectangular faces

Vertices (V):

vertices on the top triangle

vertices on the bottom triangle

Edges (E):

edges on the top triangle

edges on the bottom triangle

edges connecting the top and bottom

Euler's Formula Verification

Euler's formula: F - E + V =

Plugging in the values:

- + = 2

= 2

Therfore Euler's formula is verified for the triangular prism.

ii.

Solution

Polyhedron Analysis

Faces (F):

top triangular face

bottom pentagonal face

rectangular faces

Vertices (V):

vertices on the top triangle

vertices on the bottom pentagon

Edges (E):

edges on the top triangle

edges on the bottom pentagon

edges connecting the top and bottom

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + =

= 2

Therefore Euler's formula is verified for the polyhedron.

iii.

Solution

Hexagonal Prism Analysis

Faces (F):

hexagonal faces

rectangular faces

Vertices (V):

vertices on the top hexagon

vertices on the bottom hexagon

Edges (E):

edges on the top hexagon

edges on the bottom hexagon

edges connecting the top and bottom

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the hexagonal prism.

iv.

Solution

Polyhedron Analysis

Faces (F):

1 pentagonal face

triangular faces

Vertices (V):

vertices on the pentagon

vertex at the bottom

Edges (E):

edges on the pentagon

edges connecting to the bottom

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the polyhedron.

v.

Solution

Polyhedron Analysis

Faces (F):

square face

triangular faces

Vertices (V):

vertices on the square

vertex at the top

Edges (E):

edges on the square

edges connecting to the top

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the polyhedron.

vi.

Solution

Polyhedron Analysis

Faces (F): (all hexagons)

Vertices (V):

Edges (E):

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the polyhedron.

vii.

Solution

Polyhedron Analysis

Faces (F): (all triangles)

Vertices (V):

Edges (E):

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the polyhedron.

viii.

Solution

Polyhedron Analysis

Faces (F):

square faces

triangular face

Vertices (V):

Edges (E):

Euler's Formula Verification

Euler's formula: F - E + V = 2

Plugging in the values:

- + = 2

= 2

Therefore Euler's formula is verified for the polyhedron.

2. Is a square prism and cube are same? explain.

Solution

Square Prism Image:

Cube Image:

Is a square prism and cube are same.

Here's why:

Square Prism:

Faces: (2 square bases, 4 rectangular sides)

Edges:

Vertices:

Shape of Bases:

Shape of Sides:

Cube:

Faces:

Edges:

Vertices:

Shape of Bases:

Shape of Sides:

The main difference lies in the shape of their sides. A square prism has rectangular sides, while a cube has square sides. This means that all edges of a cube are the same length, whereas a square prism can have different lengths for its edges.

3. Can a polyhedra have 3 triangular faces only? explain.

Solution

Can a polyhedra have 3 triangular faces only?

A polyhedron needs at least three faces to meet at each corner to be a 3D shape. If you only have 3 triangles, they can only make a flat triangle or a floppy, open shape, not a closed 3D one. You'd need more faces to make a proper corner.

4. Can a polyhedra have 4 triangular faces only? explain.

Solution

Can a polyhedra have 4 triangular faces only?

Yes! This shape is called a triangular pyramid (or tetrahedron). It has a triangular base and triangular sides that meet at a point.

5. Complete the table by using Euler’s formula.

Faces (F)Vertices (V)Edges (E)
86?
5?9
?1230

Solution

Let's break down how we found the missing values:

Row 1: We had F = and V = .

Using E = F + V - 2, we get E = + - 2 = .

Row 2: We had F = and E = .

Using V = 2 + E - F, we get V = 2 + - = .

Row 3: We had V = and E = .

Using F = 2 + E - V, we get F = 2 + - = .

Threfore,

Faces (F)Vertices (V)Edges (E)
86
59
1230

6. Can a polyhedra have 10 faces, 20 edges and 15 vertices?

Solution

Can a polyhedra have 10 faces, 20 edges and 15 vertices?

Euler's formula for polyhedra states: F - E + V = 2

Let's plug in the given values: - + =

Since the result is not , this combination of faces, edges, and vertices does not satisfy Euler's formula, and therefore cannot form a polyhedron.

7. Complete the following table:

ObjectNo. of verticesNo. of edges

Solution

Explanation:

To find the number of vertices and edges, we carefully examined each 3D shape:

Rectangular Prism:

Vertices (V): Count the corners: vertices

Edges (E): Count the lines: edges

Square Pyramid:

Vertices (V): Count the corners: vertices

Edges (E): Count the lines: edges

Triangular Prism:

Vertices (V): Count the corners: vertices

Edges (E): Count the lines: edges

ObjectNo. of verticesNo. of edges
812
58
69

8. Name the 3-D objects or shapes that can be formed from the following nets .

(i).

Solution

Pyramid

(ii).

Solution

(iii).

Solution

(vi).

Solution

(v).

Solution

(vi).

Solution

(vii).

Solution

9 (i). Draw the following diagram on the check ruled book and find out which of the following diagrams makes cube ?

(a).

Solution

It can form a cube.

Cannot form a cube: The squares are arranged in a straight line and won't create a closed shape when folded.

(b).

Solution

It can form a cube.

Can form a cube: This is a classic net that forms a cube.

(c).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(d).

Solution

It can form a cube.

Cannot form a cube: There will be overlapping faces and a missing face.

(e).

Solution

It can form a cube.

Can form a cube: This is another standard net that forms a cube.

(f).

Solution

It can form a cube.

Can form a cube: This is also a valid net for a cube.

(g).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(h).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(i).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(j).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(k).

Solution

It can form a cube.

Cannot form a cube: When folded, there will be overlapping faces and a missing face.

(ii). Answer the following questions.

(a) Name the polyhedron which has four vertices, four faces?

Solution

(also known as a triangular pyramid)

(b) Name the solid object which has no vertex?

Solution

(c) Name the polyhedron which has 12 edges?

Solution

,

(d) Name the solid object which has one surface?

Solution

(e) How a cube is different from cuboid?

Solution

A cube has all its sides as , while a cuboid can have sides.

(f) Name the two shapes which have the same number of edges, vertices and faces.

Solution

,

(g) Name the polyhedron which has 5 vertices and 5 faces?

Solution

(iii). Write the names of the objects given below.

(a)

Solution

(b)

Solution

(c)

Solution

(d)

Solution