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Chapter 15: Playing with Numbers > Exercise 15.1

Exercise 15.1

1. Using divisibility rules, find which of the following numbers are divisible by 2, 5, 10 (say yes or no) in the given table. What do you observe?

Solution:

NumberDivisible by 2Divisible by 5Divisible by 10
524
1200
535
836
780
3005
4820
48630

2. Using divisibility tests, determine which of the following numbers are divisible by 2:

(a) 2144

Solution:

Divisible by 2: as digit is .

(b) 1258

Solution:

Divisible by 2: as digit is .

(c) 4336

Solution:

Divisible by 2: as digit is .

(d) 633

Solution:

Divisible by 2: as digit is .

(e) 1352

Solution:

Divisible by 2: as digit is .

3. Using divisibility tests, determine which of the following numbers are divisible by 5:

(a) 438750

Solution:

Divisible by 5: as digit is .

(b) 179015

Solution:

Divisible by 5: as digit is .

(c) 125

Solution:

Divisible by 5: as digit is .

(d) 639210

Solution:

Divisible by 5: as digit is .

(e) 17852

Solution:

Divisible by 5: as digit is .

4. Using divisibility tests, determine which of the following numbers are divisible by 10:

(a) 54450

Solution:

Divisible by 10: as digit is .

(b) 10800

Solution:

Divisible by 10: as digit is .

(c) 7138965

Solution:

Divisible by 10: as digit is .

(d) 7016930

Solution:

Divisible by 10: as digit is .

(e) 10101010

Solution:

Divisible by 10: as digit is .

5. Write the number of factors for the following:

Solution:

18 = × × . Factors: , , , , , ( factors)

24 = × × × . Factors: , , , , , , , ( factors)

45 = × × . Factors: , , , , , ( factors)

90 = × × × . Factors: , , , , , , , , , , , ( factors)

105 = × × . Factors: , , , , , , , ( factors)

6. Write any 5 numbers which are divisible by 2, 5 and 10.

Solution:

Any number ending in is divisible by 2, 5, and 10.

= , , , , .

7. A number 34A is exactly divisible by 2 and leaves a remainder 1, when divided by 5, find A.

Solution:

Since 34A is divisible by 2, A must be an digit (0, 2, 4, 6, or 8).

Since 34A leaves a remainder of 1 when divided by 5, A must be or .

The only digit that satisfies both conditions is . Therefore, A = .