Puzzles with Missing Digits

(a) 1A3 + 2B4 = 427

Instructions

Units place: 3 + 4 =

Tens place: A + B =

Hundreds place: 1 + 2 =

Since, A + B = 2, possible values: A = , B = (as digits must be between 0-9).

(b) 5B2 - 347 = 235

Instructions

Units place: 2−7 ,borrow needed → 12 - 7 =

Tens place: B−4, but we borrowed 1, so (B−1) − 4 = 3 → B − = 3 → B =

Hundreds place: 5 − 3 =

Thus, B = 8.

Instructions

Units place: 5 − 2 =

Tens place: J − K =

Hundreds place: 8 − 4 =

From J - K = L, we substitute possible values: If J = , K = , then L = which matches.

Thus, J = 7 , K = 4 , L = 3.

(d) 2T × U3 = 486

Instructions

2T represents a two-digit number where T is the digit. U3 represents a two-digit number where U is the digit. Their product is 486 and T and U are single digits we need to find.

Since 2T is a two-digit number, it can be written as + T. Similarly, U3 can be written as: U + 3

So our equation becomes: (20 + T)(10U + 3) = 486

Expanding: U + + TU + T = 486

If T = 7: The first number would be . For this to multiply to 486, the second number needs to be 486 ÷ 27 = (which in the form U3).

If T = 1: The first number would be and 486 ÷ 21 =

This works! Because 23 is in the form U3 where U = 2. Therefore: T = 1 and U = 2.

Verification: 21 × 23 =

Chapter 15: Playing with Numbers

Glossary

Puzzles with Missing Digits

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Chapter 15: Playing with Numbers

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Glossary

Puzzles with Missing Digits