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7th class > Simple Equations > Exercise 4.1

Exercise 4.1

1. Say, whether the Equation is Satisfied. (Yes/ No)

Instruction

x + 3 = 0   x = 3
x + 3 = 0   x = 0
x + 3 = 0   x = – 3
x – 7 = 1   x = 7
x – 7 = 1   x = 8
5x = 25     x = 0
5x = 25     x = 5
5x = 25     x = – 5
m3=2 m = – 6
m3=2 m = 0
m3=2 m = 6
Yes
No

Check whether the value given in the brackets is a solution to the given equation or not.

Instruction

Solve the following equations by trial and error method.

Instruction

(i) 5p + 2 = 17
Let p = 1 then 5 × 1 + 2 =
Let p = 2 then 5 × 2 + 2 =
Let p = 3 then 5 × 3 + 2 =
Equation is satisfied when p=3
Therefore, p = 3
(ii) 3m - 14 = 4
Let m = 1 then 3 × 1 - 14 =
Let m = 2 then 3 × 2 - 14 =
Let m = 3 then 3 × 3 - 14 =
Let m = 4 then 3 × 4 - 14 =
Let m = 3 then 3 × 5 - 14 =
Let m = 3 then 3 × 6 - 14 =
Equation is satisfied when m = 4
Therefore, m = 4

Write equations for the following statements:

Instruction

Write the following equations in statement forms:

Instruction

p + 4 = 15
m – 7 = 3
2m = 7
m/5 = 3
3m/5 = 6
3p + 4 = 25
4p – 2 = 18
p/2 + 2 = 8
Twice of m is 7
Adding 2 to half of p is 8
three fifth of m is 6
4 added to three times p is 25
Subtract 7 from m to get 3
one-fifth of m is 3
Subtracting 2 from 4 times p is 18
The sum of P and 4 is 15

Set up an equation in the following cases:

(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. (Take m to be the number of Parmit marbles.)

Solution:

Given: 7 more than five times Parmit marbles = Irfan's marbles = 37

Parmit's marbles = m

+ × m =

5m + 7 = 37

(ii) Laxmi’s father is 49 years old. He is 4 years older than three times Laxmi’s age. (Take Laxmi’s age to be y years.)

Solution:

Given: 4 years older than three times Laxmi's age = Laxmi's father age = 49

Laxmi's age = y

+ × y =

3y + 4 = 49

(iii) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. (Take the lowest score to be l.)

Solution:

Given: twice the lowest marks plus 7 = Highest marks = 87

Let lowest marks be l. This gives us:

l + =

2l + 7 = 87

(iv) In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be b in degrees. Remember that the sum of angles of a triangle is 180 degrees).

Solution:

Given: Iscocelese triangle

Vertex angle is twice either base angle.

Let base angle be 'b'.

So, baseangle1 = baseangle2 = b while vertexangle =

Sum of all angles = 180o

+ + 2 × = 180°

= °

4b = 180°