Powered by Innings 2

Glossary

Select one of the keywords on the left…

7th class > Simple Equations > Exercise 4.2

Exercise 4.2

1. Give first the step you will use to separate the variable and then solve the equation:

(a) x – 1 = 0

Instruction

x1=0

  • Now, to isolate x we need to the number on both sides.
  • We get: x1+1= 0+1
  • Thus, x =
  • Therefore, solution for x1 = 0 is x = 1.

Instruction

(b) x + 1 = 0

x+1=0

  • Now, to isolate x: we have to the number to x+1 on both sides.
  • We get: x+11 = 01
  • Thus, x =
  • Therefore, solution for x+1=0 is x=1

Instruction

(c) x – 1 = 5

x1=5

  • Now,to isolate x: we need to the number on both sides.
  • We get: x1+1 = 5+1
  • Thus, x =
  • Therefore, the solution for x1 = 5 is x=6.

(d) x + 6 = 2

Instruction

x+6=2

  • Now, to isolate x: we need to the number on both sides.
  • We get: x+66=26
  • Thus, x =
  • Therefore, the solution for x+6=2 is x = 4.

(e) y – 4 = – 7

Instruction

y4=7

  • Now, to isolate x: we need to the number on both sides.
  • We get: y4+4=7+4
  • Thus, x =
  • Therefore, the solution for x+4=7 is x = 3.

(f) y – 4 = 4

Instruction

y4=4

  • Now, to isolate y: we need to the number on both sides.
  • We get: y4+4 = 4+4
  • Thus, y =
  • Therefore, the solution for y4= 4 is y = 8.

(g) y + 4 = 4

Instruction

y+4=4

  • Now,to isolate y we need to the number on both sides.
  • We get: y+44 = 44
  • Thus, y =
  • Therefore,the solution for y+4= 4 is y=0.

(h) y + 4 = – 4

Instruction

y+4=4

  • Now, to isolate y we need to  the number on both sides.
  • We get: y+44 = 44
  • Thus, y =
  • Therefore, the solution for y+4 = 4 is y = 8.

2. Give first the step you will use to separate the variable and then solve the equation:

Instruction

3. Give the steps you will use to separate the variable and then solve the equation:

(a) 3n – 2 = 46

Instruction

To isolate n, first we add on both sides.
Thus, =
Now dividing by on both sides.
We get: n = .
The solution for 3n2 = 46 is n = 16.

(b) 5m+7=17

Instruction

To isolate p, first we multiply by on both sides.
Thus, =
Now, divide by on both sides.
We get: p = .
The solution for 20p3=40 is p=60.

(c) 20p3=40

Instruction

Add 4 to eight times a number; you get 60.
Let the number be x.
From the question we know, x + =
Upon subtracting and dividing by on both sides and solving we get: x = .
Therefore, x = 7.

(d) 3p10=6

Instruction

To isolate p, first we multiply by on both sides.
Thus, =
Now, divide by on both sides.
We get: p =
The solution for 3p10=6 is p = 20.

Solve the following equations.

4. Solve the following equations.

Instruction

10p = 100
10p + 10 = 100
p/4 = 5
-p/3 =5
3p/4 = 6
3s = -9
3s + 12 = 0
3s = 0
2q = 6
2n-6 = 0
2q+6 = 0
2m+6 = 12
p = 20
s = 0
p = -15
n = 3
m = 3
p = 8
s = -4
p = 10
q = -3
p = 9
s = -3
q = 3