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7th class > Simple Equations > Exercise 4.3

Exercise 4.3

1. Set up equations and solve them to find the unknown numbers in the following cases:

Instruction

Add 4 to eight times a number; you get 60.
Let the number be x.
From the question we know, x + =
Upon subtracting and dividing by on both sides and solving we get: x = .
Therefore, x = 7.
One-fifth of a number minus 4 gives 3.
Let the number be x.
From the question we know: x - =
Upon adding and then multiplying by 5 on both sides and solving we get: x = .
Therefore, x = 35.
If I take three-fourths of a number and add 3 to it, I get 21.
Let the number be x.
From the question we know, x + =
Upon subtracting and then multiplying by 4/3 on both sides and solving we get: x = .
Therefore, x = 24.
When I subtracted 11 from twice a number, the result was 15.
Let the number be x.
From the question we know, - =
Upon adding and then dividing by on both sides and solving we get, x = .
Therefore, x = 14.
Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.
Let the number be x.
From the question we know, - =
Upon subtracting and then dividing by on both sides and solving we get, x = .
Therefore, x = 14.
Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.
Let the number be x.
From the question we know, (x + )/ =
Upon multiplying and then subtracting on both sides we get, x = .
Therefore, x = 21.
Anwar thinks of a number. If he takes away 7 from 52 of the number, the result is 23.
Let the number be x.
From the question we know, x - =
Upon adding and then dividing by on both sides and solving we get, x = .
Therefore, x = 12.

Solve the following:

(a) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?

Solution:

Let lowest score be m.

Given: Twice the lowest score + 7 = Highest mark

× m + 7 =

To isolate m, subtract on both sides.

2m + 7 - 7 = 87 - 7 which gives 2m =

Divide by on both the sides.

m =

(b) In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180°).

Solution:

Let base angle 1 = base angle 2 = b

Given: vertex angle = 40°

b + b + = °

To isolate b, subtract on both sides.

2b + 40 - 40 = 180° - 40° which gives us 2b = °

Dividing by on both the sides.

b = °

(c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?

Solution:

Let Rahul's runs be r.

Given: Sachin score =

r + = -

=

Divide by on both the sides.

r = runs

Thus, Rahul scored 66 runs while Sachin scored 2r i.e. 2 × 66 = runs.

3. Solve the following:

(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?

Solution:

Let Parmit's marbles be m

Given: 5 × Parmit's marbles + 7 = Irfan's marbles = 37

m + = 37

To isolate m, subtract on both sides.

5m + 7-7 = 37-7 which gives us m =

Divide by on both the sides.

m =

(ii) Laxmi’s father is 49 years old. He is 4 years older than three times Laxmi’s age. What is Laxmi's age?

Solution:

Let Laxmi's age = m

Given: 3 × Laxmi's age + 4 = Laxmi's father age = 49

× m + =

To isolate m, subtract on both sides.

3m + 4 - 4 = 49 - 4 which gives =

Divide by on both the sides.

m =

(iii) People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?

Solution:

Let the number of fruit trees be 'f'.

Given: 3 × Fruit trees + 2 = Non-fruit trees =

× f + = 77

To isolate f, subtract on both sides.

3f + 2-2 = 77-2 giving us =

Divide by on both the sides.

Thus, f =

Thus, the number of fruit trees are 25.

Solve the following riddle:

I am a number,

Tell my identity!

Take me seven times over

And add a fifty!

To reach a triple century

You still need forty!

Instruction

Let the number be n

  • Taking the number to be n, we multiply it by .
  • We now add, to 7n: .
  • This resulting number falls short of a triple century by 40 i.e. the number is equal to .
  • Thus, the equation is 7n+50 = 260.
  • To starting solving, subtract by on both sides.
  • Now, divide by on both sides.
  • We get: n = .
  • Thus, the number is 30.