Exercise 9.3
1. State which of the following are equations.
2. Write LHS and RHS of the following equations.
Solution :
| Equation | LHS (Left-Hand Side) | RHS (Right-Hand Side) |
|---|---|---|
| (i) x – 5 = 6 | x – 5 | |
| (ii) 4y = 12 | 4y | |
| (iii) 2z + 3 = 7 | 7 | |
| (iv) 3p = 24 | ||
| (v) 4 = x – 2 | 4 | |
| (vi) 2a – 3 = –5 |
3(i) .Solve the following equations by Trial & Error method.
(i) x + 3 = 5
Solution :
| Value of x | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 + 3 = | |||
| 2 + 3 = |
We find that for x =
3(ii) Solve the following equations by Trial & Error method.
(ii) y – 2 = 7
| Value of y | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 | 1 – 2 = | ||
| 2 | 2 – 2 = | ||
| 3 | 3 – 2 = | ||
| 4 | 4 – 2 = | ||
| 5 | 5 – 2 = | ||
| 6 | 6 – 2 = | ||
| 7 | 7 – 2 = | ||
| 8 | 8 – 2 = | ||
| 9 | 9 – 2 = |
We find that for y =
3(iii) Solve the following equations by Trial & Error method.
(iii) a – 2 = 6
| Value of a | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 | 1 – 2 = | ||
| 2 | 2 – 2 = | ||
| 3 | 3 – 2 = | ||
| 4 | 4 – 2 = | ||
| 5 | 5 – 2 = | ||
| 6 | 6 – 2 = | ||
| 7 | 7 – 2 = | ||
| 8 | 8 – 2 = |
We find that for a =
Solve the following equations by Trial & Error method.
(iv) 5y = 15
| Value of y | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 | 5 × 1 = | ||
| 2 | 5 × 2 = | ||
| 3 | 5 × 3 = |
We find that for y =
(v) 6n = 30
| Value of n | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 | 6 × 1 = | ||
| 2 | 6 × 2 = | ||
| 3 | 6 × 3 = | ||
| 4 | 6 × 4 = | ||
| 5 | 6 × 5 = |
We find that for n =
(vi) 3z = 27
| Value of z | Value of LHS | Value of RHS | Whether LHS and RHS are equal |
|---|---|---|---|
| 1 | 3 × 1 = | ||
| 2 | 3 × 2 = | ||
| 3 | 3 × 3 = | ||
| 4 | 3 × 4 = | ||
| 5 | 3 × 5 = | ||
| 6 | 3 × 6 = | ||
| 7 | 3 × 7 = | ||
| 8 | 3 × 8 = | ||
| 9 | 3 × 9 = |
We find that for z =