Moderate Level Worksheet Questions

Data handling involves collecting, organizing, analyzing, and interpreting data. Understanding measures of central tendency and data representation helps us make sense of information and draw meaningful conclusions.

First, let's explore basic concepts of data handling and statistical measures.

1. Define a bar graph. Graph with rectangular barsCircular graph with sectorsLine connecting pointsTable with numbers

Awesome! A bar graph uses rectangular bars to represent data visually.

2. What is the mode of the data: 4, 6, 3, 4, 2, 4, 5, 3? 4365

Great job! 4 appears 3 times, more than any other value.

3. Find the mean of 10, 20, 30, 40, 50. 30253540

Perfect! Mean = (10+20+30+40+50) ÷ 5 = 150 ÷ 5 = 30.

4. What is the range of the data: 15, 22, 19, 25, 30, 18? 15301012

Excellent! Range = 30 - 15 = 15.

5. Define "frequency" in data handling. Number of times a value occursAverage of all valuesMiddle valueHighest value

Super! Frequency shows how often each value appears in the dataset.

6. Which type of bar graph is used to compare two related sets of data? Double bar graphSimple bar graphHistogramPie chart

That's correct! Double bar graphs compare two related datasets side by side.

7. What is the median of 2, 5, 7, 8, 10? 7586

Well done! The median is the middle value when arranged in order.

8. The marks scored by 5 students are: 12, 18, 15, 10, 20. Find the mean marks. 15161417

Brilliant! Mean = (12+18+15+10+20) ÷ 5 = 75 ÷ 5 = 15.

9. What is a histogram? Bar graph for continuous dataGraph with linesCircular chartData table

You nailed it! Histograms show frequency distribution of continuous data.

10. Give an example where data is collected through observation. Traffic countSurvey questionnaireOnline pollWritten test

Perfect! Traffic counting involves direct observation and recording.

Drag each method to its correct category:

Part B: Short Answer Questions (2 Marks Each)

1. The marks obtained by 8 students in a test are: 15, 20, 10, 25, 20, 15, 10, 30. Prepare a frequency table.

Step 1: Identify unique values

Unique marks: 10, 15, 20, 25, 3010, 15, 20, 25

Step 2: Count frequencies

10: appears times

15: appears times

20: appears times

25: appears time

30: appears time

Step 3: Verify

Total frequency = 2 + 2 + 2 + 1 + 1 =

Excellent! Your frequency table is complete and accurate.

2. The weights (in kg) of 10 students are: 40, 42, 38, 45, 42, 40, 38, 39, 45, 42. Find the mode.

Step 1: Count frequencies

38 kg: times

40 kg: times

42 kg: times

45 kg: times

39 kg: time

Step 2: Identify mode

Most frequent weight = kg (appears 3 times)

Perfect! 42 kg is the mode.

3. Find the median of: 18, 20, 15, 25, 22, 18, 20.

Step 1: Arrange in ascending order

Ordered data: , , , , , ,

Step 2: Find middle position

Number of values = 7

Middle position = (7 + 1) ÷ 2 = th position

Step 3: Identify median

4th value in ordered list =

Great work! The median is 20.

4. Sports data: Cricket: 30, Football: 25, Hockey: 20, Badminton: 15.

Step 1: Compare values

Cricket: {.reveal(when="blank-22")}Football:

Hockey:

Badminton:

Highest participation =

Step 2: Calculate total

Total students = 30 + 25 + 20 + 15 =

Excellent analysis! Cricket has highest participation with 90 total students.

5. Find the range and mean of the data: 12, 15, 10, 20, 18, 12.

Step 1: Find range

Highest value =

Lowest value =

Range = 20 - 10 =

Step 2: Calculate mean

Sum = 12 + 15 + 10 + 20 + 18 + 12 =

Number of values =

Mean = 87 ÷ 6 =

Outstanding! Range = 10, Mean = 14.5.

Part C: Long Answer Questions (4 Marks Each)

1. Marks of 20 students: 12, 15, 18, 20, 22, 15, 14, 18, 19, 20, 18, 17, 15, 14, 16, 19, 20, 21, 18, 15.

Step 1: Create frequency table

Count occurrences of each mark:

12: time

14: times

15: times

16: time

17: time

18: times

19: times

20: times

21: time

22: time

Step 2: Calculate sum and mean

Sum of all marks =

Mean marks = ÷ 20 =

Perfect! Mean marks = 17, with frequencies correctly calculated.

2. Heights (in cm): 140, 145, 150, 155, 150, 160, 145, 150, 155, 150, 145, 160.

Step 1: Count frequencies

140 cm: time

145 cm: times

150 cm: times (highest frequency)

155 cm: times

160 cm: times

Step 2: Find mode

Mode = cm (most frequent)

Step 3: Arrange for median

Ordered: 140, 145, 145, 145, 150, 150, 150, 150, 155, 155, 160, 160

Number of values = 12 (even)

Median = (6th + 7th values) ÷ 2 = (150 + 150) ÷ 2 = cm

Excellent! Mode = 150 cm, Median = 150 cm.

3. Histogram data:

Step 1: Analyze frequencies

Highest frequency =

Modal class = 145-150150–155

Lowest frequency =

Class with lowest frequency = 130-135135–140

Step 2: Calculate total

Total students = 4 + 6 + 8 + 10 + 6 =

Great analysis! Modal class is 145-150 with 34 total students.

4. Daily temperatures for 10 days: 32, 35, 34, 36, 33, 34, 35, 37, 36, 35.

Step 1: Count frequencies

32°C: time

33°C: time

34°C: times

35°C: times

36°C: times

37°C: time

Step 2: Find mode

Mode = °C

Step 3: Calculate mean

Sum = 32 + 35 + 34 + 36 + 33 + 34 + 35 + 37 + 36 + 35 = °C

Mean temperature = 347 ÷ 10 = °C

Outstanding! Mode = 35°C, Mean = 34.7°C.

Test your understanding with these multiple choice questions:

For each question, click on the correct answer:

1. The mean of 6, 8, 10, 12 is:

(a) 8 (b) 9 (c) 10 (d) 11

Super job! Mean = (6+8+10+12) ÷ 4 = 36 ÷ 4 = 9.

2. The range of 15, 22, 19, 25 is:

(a) 10 (b) 8 (c) 5 (d) 7

Well done! Range = 25 - 15 = 10.

3. In a bar graph, the heights of bars represent:

(a) Categories (b) Frequency (c) Class intervals (d) None

That's right! Bar heights show frequency or count of data.

4. The mode of 5, 7, 5, 8, 9, 5, 7 is:

(a) 5 (b) 7 (c) 8 (d) 9

Correct! 5 appears 3 times, more than any other value.

5. Which of these is not a measure of central tendency?

(a) Mean (b) Median (c) Mode (d) Range

Fantastic! Range measures spread, not central tendency.