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Data Handling > Presentation of data

Presentation of data

We have seen last year how information collected could be first arranged in a frequency distribution table and then this information could be put as a visual representation in the form of pictographs or bar graphs. You can look at the bar graphs and make deductions about the data. You can also get information based on these bar graphs. For example, you can say that the mode is the longest bar if the bar represents the frequency.

Choosing a Scale

We know that a bar graph is a representation of numbers using bars of uniform width and the lengths of the bars depend upon the frequency and the scale you have chosen.

For example: In a bar graph where numbers in units are to be shown, the graph represents one unit length for one observation and if it has to show numbers in tens or hundreds, one unit length can represent 10 or 100 observations. Consider the following examples:

Two hundred students of 6th and 7th classes were asked to name their favourite colour so as to decide upon what should be the colour of their school building. The results are shown in the following table. Represent the given data on a bar graph.

Favourite ColourNumber of Students
Red43
Green19
Blue55
Yellow49
Orange34

Solution :

Lets first choose a suitable scale as follows:

Start the scale at 0. The greatest value in the data is 55, so end the scale at a value greater than 55, such as .

Use equal divisions along the axes, such as increments of 10. You know that all the bars would lie between 0 and 60. We choose the scale such that the length between 0 and 60 is neither too long nor too small. Here we take 1 unit for 5 students.

One the X-axis we represent each color with a scale of 10.

We then draw and label the graph as shown. The first bar is drawn for you, draw the bar graphs for remaining colours.

We see that green is 19. So start from the green point at 10 on x-axis and drag and draw a rectangle bar upto height 19.

Great. Now do the same for Blue.

Red, Green and Blue done. Now do the same for Yellow.

Just one more left. Draw the bar for Orange.

All done. We have drawn a bar graph representation of the tabular data provided. Now answer the following questions with the help of the bar graph:

(i) Which is the most preferred colour and which is the least preferred?

Solution : is the most preferred colour (Because the bar representing it is the tallest).

is the least preferred colour. (Because the bar representing it is the shortest).

(ii) How many colours are there in all? What are they?

Solution : There are colours. They are , , , and . (These are observed on the horizontal line)

Following data gives total marks (out of 600) obtained by six children of a particular class. Represent the data on a bar graph.

StudentsMarks Obtained
Ajay450
Bahubali500
Deepak300
Farzi360
Sushma400
Devi540

Instruction

Drawing double bar graph

Consider the following two collections of data giving the average daily hours of sunshine in two cities Delhi and Mumbai for all the twelve months of the year.

In Delhi

Average hours ofsunshineJanFebMarAprMayJuneJulyAugSepOctNovDec
55.56678766654

In Mumbai

Average hours ofsunshineJanFebMarAprMayJuneJulyAugSepOctNovDec
44.54.5688777654

By drawing individual bar graphs you could answer questions like

(i) In which month does each city has maximum sunlight? or

(ii) In which months does each city has minimum sunlight?

However, to answer questions like “In a particular month, which city has more sunshine hours”, we need to compare the average hours of sunshine of both the cities.

To do this we will learn to draw what is called a double bar graph giving the information of both cities side-by-side. This bar graph shows the average sunshine of both the cities.

For each month we have two bars, the heights of which give the average hours of sunshine in each city. From this we can infer that except for the month of April, there is always more sunshine in Mumbai than in Delhi. You could put together a similiar bar graph for your area or for your city.

A mathematics teacher wants to see, whether the new technique of teaching she applied after quarterly test was effective or not. She takes the scores of the 5 weakest children in the quarterly test (out of 25) and in the half yearly test (out of 25).

StudentsQuarterly Half yearly
Ashish1015
Arun1518
Devesh1216
Priya2021
Suma915

Solution :

She draws the adjoining double bar graph. Look at the graph can you quickly say whether the marks have improved?

1. The bar graph shows the result of a survey to test water resistant watches made by different companies.

Each of these companies claimed that their watches were water resistant. After a test the above results were revealed.

(a) Can you work out a fraction of the number of watches that leaked to the number tested for each company?

Solution:

A fraction of the number of watches that leaked to the number tested for each company are :

For A, 2040 =

For B, 1040 =

For C, 1540 =

For D, 2540 =

(b) Could you tell on this basis which company has better watches?

Clearly , 10<15<20<25

= 1040 < 1540 < 2040 < 2540

Thus, a company with a fraction i.e., company B has better watches.

2.Sale of English and Hindi books in the years 1995, 1996,1997 and 1998 are given below:

Years1995199619971998
English350400450620
Hindi500525600650

Draw a double bar graph and answer the following questions:

(a) In which year was the difference in the sale of the two language books least?

To choose an appropriate scale, we make equal divisions taking increments of 100. Thus, 1 unit = 100 books.

Clearly, the difference in the sale of the two language books is least in the year .

(b) Can you say that the demand for English books rose faster? Justify.

Since, the bar graph of the sale, of English books becomes longer faster, so the demand for English books rose .

Circle Graph or Pie Chart

Have you ever come across data represented in circular form as shown?

Age groups of people in a town

These are called circle graphs. A circle graph shows the relationship between a whole and its parts.

Here, the whole circle is divided into sectors. The size of each sector is proportional to the activity or information it represents.

Instructions

For example, in the above graph, the size of the sector is proportional to the hours spent in sleeping.
Fraction of hours spent sleeping =number of sleeping hourswhole day = 8hours24 hours =
So, this sector is drawn as 13 rd part of the circle. Similarly, the proportion of the sector for hours spent in school =number of school hourswhole day = 6 hours24 hours =
So, this sector is drawn as 14 th part of the circle. Similarly, the size of other sectors can be found.

Now, add up the fractions for all the activities. Do you get the total as one?

A circle graph is also called a pie chart.

Try these

1. Answer the following questions based on the pie chart given

(i) Which type of programmes are viewed the most?

(ii) Which two types of programmes have number of viewers equal to those watching sports channels?

2. Each of the following pie charts gives you a different piece of information about your class. Find the fraction of the circle representing each of these information

Fraction of the girls in class =

Fraction of the boys in class =

Fraction of students walking to school =

Fraction of students coming to school by bus or car =

Fraction of students coming to school by cycle =

Fraction of students that love Maths =

Fraction of students That hate Maths =

The favourite flavours of ice-creams for students of a school is given in percentages as follows.

FlavoursPercentage of student preference
Chocolate50 %
Vanilla25 %
Other flavours25 %

The total angle at the centre of a circle is °.

The central angle of the sectors will be a fraction of 360°. We make a table to find the central angle of the sectors (below Table).

FlavoursStudents in per cent preferring the flavoursIn fractionsFraction of 360°
Chocolate50%50100=12 of 360° = °
Vanilla25%25100=14 of 360° = °
Other flavours25%25100=14 of 360° = °

Example 1

Adjoining pie chart gives the expenditure (in percentage) on various items and savings of a family during a month.

Instructions

(i) On which item, the expenditure was maximum?
Expenditure is maximum on .
(ii) Expenditure on which item is equal to the total savings of the family?
Expenditure on is the same(i.e., 15%) as the savings of the family.
(iii) If the monthly savings of the family is ₹3000, what is the monthly expenditure on clothes?
15% represents 3000 Therefore, 10% represents = 300015 x 10 = ₹

2. On a particular day, the sales (in ₹ ) of different items of a baker’s shop are given below.

ItemsSales ( in ₹)
Ordinary bread320
Fruit bread80
Cakes and Pastries160
Biscuits120
Others40
Total720

Now, we make the pie chart

Solution:

We find the central angle of each sector. Here the total sale = ₹ 720. We thus have this table.

ItemSales (in ₹)In fractionsCentral Angle
Ordinary Bread320320720=49 × 360° = °
Biscuits 120120720=16 × 360° = °
Cakes and pastries 160160720=29 × 360° = °
Fruit Bread8080720=19 × 360° = °
Others 4040720=118 × 360° = °

Try These

Draw a pie chart of the data given below.

The time spent by a child during a day.

ActivityTime Spent (hours)
Sleep8
School6
Home work4
Play4
Others2

THINK, DISCUSS AND WRITE

Which form of graph would be appropriate to display the following data.

  1. Production of food grains of a state:
YearProduction(in lakh tons)
200160
200250
200370
200455
200580
200685

2. Choice of food for a group of people.

Favourite foodNumber of people
North Indian30
South Indian40
Chinese25
Others25
Total120

The daily income of a group of a factory workers.

Daily Income (in Rupees)No. of workers(in factory)
75-10045
100-12535
125-15055
150-17530
175-20050
200-225125
225-250140
Total480