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Chapter 12: Factorisation > Factorisation using Identities

Factorisation using Identities

Factorisation using identities

When dealing with expressions, you might have observed that the form of the expressions we encounter are often repetitive. There are a good number of expressions which have a standard form of factorisation which have been proven over time. These identities include the following:

a+b2 = a2 + b2 + 2ab (I)

ab2 = a2 + b2 - 2ab (II)

(a + b)(a – b) = a2 - b2 (III)

Therefore, if the expression at hand, has a form that fits the RHS of any one of these identities, then the expression corresponding to the LHS of the identity is the desired factorisation.

Example 4: Factorise x2+8x+16

Instructions

x2+8x+16

  • The above is in the form of the identity: where a and b are two integers.
  • We see that a = x while b =
  • Thus, the factorised form =
  • Which gives us the above factorised answer

Example 5: Factorise 4y212y+9

Instructions

4y212y+9

  • The above is in the form of the identity: where a and b are two integers.
  • We see that a = while b = 3
  • Thus, the factorised form =
  • Which gives us the above factorised answer

Example 6: Factorise 49p236

Instructions

49p236

  • The above is in the form of the identity: where a and b are two integers.
  • We see that a = while b = 6
  • Thus, the factorised form =
  • Which gives us the above factorised answer

Example 7: Factorise a22ab+b2c2

Instructions

a22ab+b2c2

  • In the above expression: the first three terms are in the form of the identity: where a and b are two integers.
  • Factorising the first three terms, we get:
  • The resulting expression is in the form: where a and b are random integers (not the ones mentioned in the current problem).
  • Thus, the resulting factorised form becomes
  • Which gives us the above factorised answer

Example 8: Factorise m4256

Instructions

m4256

  • Notice that: m4=m22 and 256 = squared.
  • Thus, the above expression is in the form of the identity: where a and b are two integers.
  • Doing this, we get:
  • We see that the expression m216 can be further factorised using the same identity.
  • Thus, the resulting factorised form becomes
  • Which gives us the above factorised answer