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Chapter 12: Factorisation > Method of Common Factors

Method of Common Factors

Factorise 2x + 4 (Write each term as a product of irreducible factors)

We can write 2x =

and 4 = x

Therefore we get,

2x + 4 = (2 x) + (2×2)

We notice that the factor 2 is common to both the terms. Using the distributive law:

2(x + 2) = (2×x) + (2×2) (for the above case)

Therefore, we can write:

2x + 4 = 2×(x + 2) = 2(x + 2)

Thus, the expression 2x + 4 is equal to 2 (x + 2). In this form we can easily see the factors for the expression: 2 and (x + 2). These factors as we know, are .

Factorise 5xy + 10x and find the common factor between the two terms

Instructions

5xy+10x

  • The common factor :
  • Factorised form =
  • Taking out the common factor
  • Which gives us the above answer

Therefore, 5xy + 10x = 5 x (y + 2) which is the factorised form.

Example 1: Factorise the following expressions: 12a2b+15ab2

Instructions

12a2b+15ab2

  • The common factor(s) product :
  • Thus, factorised form =
  • Taking out the common factor
  • Which gives us the above answer

Example 2: Factorise 10x218x3+14x4

Instructions

10x218x3+14x4

  • The common factor(s) product :
  • Thus, factorised form =
  • Taking out the common factor
  • Which gives us the above answer

TRY THESE

Factorise: (i) 14pq+35pqr

Instructions

14pq+35pqr

  • The common factor(s) product :
  • Thus, factorised form =
  • Taking out the common factor
  • Which gives us the above answer

(ii) 22y33z

Instructions

22y33z

  • The common factor(s) product :
  • Thus, factorised form =
  • Taking out the common factor
  • Which gives us the above answer

(iii) 12x + 36

Instructions

12x + 36 =
Thus, the factorised form is: 12(x+3)