Exercise 6.1
1. In ∆ PQR, D is the mid-point of QR.
PM is ?
PD is ?
Is QM = MR ?
Solution:
PM is
Also, PD divides QR into equal parts as D is the mid-point of
Therefore, PM is
Also, D is the mid-point of
Therefore, QD = DR and hence PD is the
Is QM = MR ?
2. Draw rough sketches for the following:
a
(a) In ∆ABC, BE is a median.
Solution:
A median of a triangle is a line segment that is drawn from a vertex to the opposite side of the vertex, and it divides the opposite side into two
b
(b) In ∆PQR, PQ and PR are altitudes of the triangle.
Solution:
An altitude of a triangle is defined as a
c
(c) In ∆XYZ, YL is an altitude in the exterior of the triangle.
Solution:
An altitude of a triangle is defined as a perpendicular drawn from the vertex to the line containing the opposite side of the triangle. The rough sketch of ∆XYZ, YL is an altitude in the
3. Verify by drawing a diagram if the median and altitude of an isosceles triangle can be same.
Solution:
Given that the triangle is an
It is required to verify if the median and altitude of the given triangle can be the same. To do this, construct an isosceles triangle. An isosceles triangle has two
Construct an isosceles triangle △ABC with sides AB = AC and draw a median AL that divides the base of the triangle into
From the triangle, it can be seen that the median makes a
So, AL is the
Hence verified, AL is the median and altitude of the given triangle △ABC.