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7th class > The Triangles and its Properties > Exercise 6.2

Exercise 6.2

1. Find the value of the unknown exterior angle x in the following diagrams:

a

(i) Find the value of x in the following diagram.

(i)

According to the exterior angle property, the of the opposite interior angles equals the exterior angle of a triangle.

Hence,

x = 70° + 50° = °

The value of x is 120°.

b

(ii) Find the value of x in the following diagram.

(ii)

Solution:

According to the exterior angle property,the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

Hence,

x = 65° + ° = °

The value of x is 110°.

c

(iii) Find the value of x in the following diagram.

(iii)

Solution:

According to the exterior angle property, the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

Hence,

x = 30° + ° = °

The value of x is 70°.

d

(iv) find the value of x in the following diagram.

(iv)

Solution:

According to the exterior angle property, the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

Hence,

x = 60° + 60° = °

The value of x is 120°.

e

(v) Find the value of x in the following diagram.

(v)

Solution:

According to the exterior angle property, the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

Hence,

x = 50° + ° = °

The value of x is 100°.

f

(vi) Find the value of x in the following diagram.

(vi)

Solution:

According to the exterior angle property, the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

Hence,

x = 30° + ° = °

The value of x is 90°.

2. Find the value of the unknown interior angle x in the following figures.

According to the exterior angle property, the sum of the opposite non-adjacent interior angles equals the exterior angle of a triangle.

a

(i) Find the value of x in the following diagram.

(i)

Solution:

x + ° = °

Subtract 50° from both sides of the equation.

x = °° = °

The value of x is 65°.

b

(ii) Find the value of x in the following diagram.

(ii)

Solution:

x + ° = °

Subtract 70° from both sides of the equation.

x = 100° − 70° = °

The value of x is 30°.

c

(iii) Find the value of x in the following diagram.

(iii)

Solution:

x + ° = °

Subtract 90° from both sides of the equation.

x + 90° − 90° = 125° − 90° = °

The value of x is 35°.

d

(iv) Find the value of x in the following diagram.

(iv)

Solution:

x + ° = °

Subtract 60° from both sides of the equation.

x + 60° − 60° = 120° − 60° = °

The value of x is 60°.

e

(v) Find the value of x in the following diagram.

(v)

Solution:

x + ° = °

Subtract 30° from both sides of the equation.

x + 30° − 30° = 80° − 30° = °

The value of x is 50°.

f

(vi) Find the value of x in the following diagram.

(vi)

Solution:

x + ° = °

Subtract 35° from both sides of the equation.

x + 35° − 35° = 75° − 35° = °

The value of x is 40°.